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77julia77 [94]
3 years ago
14

Pulling up on a rope, you lift a 4.25 kg bucket of water from a well with an acceleration of 1.80 m/s2 . What is the tension in

the rope?
Physics
1 answer:
sattari [20]3 years ago
8 0

Answer:

49.3 N

Explanation:

Given that Pulling up on a rope, you lift a 4.25 kg bucket of water from a well with an acceleration of 1.80 m/s2 . What is the tension in the rope?

The weight of the bucket of water = mg.

Weight = 4.25 × 9.8

Weight = 41.65 N

The tension and the weight will be opposite in direction.

Total force = ma

T - mg = ma

Make tension T the subject of formula

T = ma + mg

T = m ( a + g )

Substitutes all the parameters into the formula

T = 4.25 ( 1.8 + 9.8 )

T = 4.25 ( 11.6 )

T = 49.3 N

Therefore, the tension in the rope is 49.3 N approximately.

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Two skiers start at the same place at the top of the hill, and finish at the same place at the bottom. Skier A takes a straight,
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Given

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3 years ago
Pablo Sandoval throws a baseball with a horizontal component of velocity of 25 m/s after two seconds the ball is 40 m above the
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Answer:

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Which type of seismic wave does not travel through liquid?
notka56 [123]

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8 0
3 years ago
If this did not happen, what would be the approximate force on an eardrum of area 0.22 cm2 if a change in altitude of 1500 m tak
jeyben [28]

Complete Question

When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?

Answer:

The value is F    = 0.60 \  N

Explanation:

From the question we are told that

   The area of the ear drum is  A = 0.5 \  cm^2 = 0.50 *10^{-4} \  m^2

    The change in altitude is  \Delta d  = 950 \  m

Generally the change in pressure is mathematically represented as

       \Delta P = \frac{F}{A}

This can also be mathematically represented as

      \Delta P = \rho * g *  \Delta d

So

       \frac{F}{A}     = \rho * g *  \Delta d

=>    F    = \rho * g *  \Delta d  *  A

=>    F    = \rho * g *  \Delta d  *  A

Here \rho is the density of dry air with value  \rho =  1.29 \ kg /m^3

So

     F    = 1.29 * 9.8 *  950  *  0.50 *10^{-4}

=> F    = 0.60 \  N

3 0
3 years ago
This is about resistance, voltage, current<br>any answers greatly appreciated
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The electrical resistance<span> of a circuit component or device is defined as the ratio of the voltage applied to the electric current whichflows through it: If the </span>resistance<span> is constant over a considerable range of voltage, then Ohm's law, I = V/R, can be used to predict the behavior of the material.b
</span>
6 0
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