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3 years ago

If you act without reason or sound judgement, people will describe you as __________.

Physics

1 answer:

EastWind [94]3 years ago

8 0

Answer:

irrational

Explanation:

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A certain radar installation tracks airplanes by transmitting electromagnetic radiation of wavelength 4.0 cm.

Anna35 [415]

the wavelength equation is

speed (of light in this case)= wavelength (m) x frequency

3x10^8m/s / .07m = f

frequency= 4 285 714 286 hertz

b) Total distance= 4.8 km (4,800 m)

Speed = 3x10^8 m/s

d=st

t= d/s

t= 4,800 m/3x10^8m/s

t= 1x10^-5 seconds

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3 years ago

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Someone help me with this ASAP!!!

In-s [12.5K]

Explanation:

the answer is y=strong winds move sand dunes in the desert

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3 years ago

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The formula v = √ 2.3 r models the maximum safe speed, v , in miles per hour, at which a car can travel on a curved road with ra

Archy [21]

Answer:

562 miles per hour.

Explanation:

As given in the question, the formula for the maximum speed on a curved road is

$v=\sqrt{2.3}$ $r$

Given value of $r=370$ feet

So the maximum safe speed will be

$v=\sqrt{2.3} \times 370 = 1.52\times 370 = 562.4$ miles per hour.

Rounding off to the nearest whole number we get the maximum safe speed at the curved road is 562 miles per hour.

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4 years ago

You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th

PolarNik [594]

Answer: The Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

Explanation:

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

$Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}$

where,

Y = Young's Modulus

F = force exerted by the weight = $m\times g$

m = mass of the ball = 10 kg

g = acceleration due to gravity = $9.81m/s^2$

l = length of wire = 2.6 m

A = area of cross section = $\pi r^2$

r = radius of the wire = $\frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m$ (Conversion factor: 1 m = 1000 mm)

$\Delta l$ = change in length = 1.99 mm = $1.99\times 10^{-3}m$

Putting values in above equation, we get:

$Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2$

Hence, the Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

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4 years ago

the diagram deliver of uniform mass supported at the middle point six Queens of equal mass are placed at mark 4 on on the lift h

gtnhenbr [62]

Answer:

hmm I don’t understand

Explanation:

5 0

3 years ago