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3 years ago

A 62 kg box is lifted 12 meters off the ground. How much work was done?

Physics

2 answers:

victus00 [196]3 years ago

7 0

Answer: 7.3 kJ

Explanation:

Work = gravitational potential energy

Amount of work done to lift the box off the ground is stored in the form gravitational potential energy.

W = m g h

where m is the mass = 62 kg

g is the acceleration due to gravity = 9.81 m/s²

h is the height = 12 m

W = 62 kg × 9.81 m/s² × 12 m = 7298. 6 J = 7.3 kJ

OleMash [197]3 years ago

6 0

7291.2 I hope this is right

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It's 1.0000042 times longer in summer than in winter. It represents a 1.6 centimeters difference between seasons.

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4 years ago

Determine the direction of the force that will act on the charge in each of the following situations. A negative charge moving t

wlad13 [49]

Answer:

a) DOWN direction, b) directed INTO THE SCREEN, c) F = 0

Explanation:

The direction of the force is

for electric force

F = q E

where we assume a positive test charge, for which the force has the direction of the electric field.

For a magnetic field

in this case the direction of the force is given by the right hand rule.

For a positive test charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm gives the direction of force for a positive charge.

F = q v x B

Let us apply these considerations to our case.

a) negative charge moving to the left

in a magnetic field points away from the screen

In this case the thumb goes to the left, the fingers extended outwards and the palm points upwards, but since the charge is negative the force has a DOWN direction.

b) negative charge moves to the left

in electric field it points off the screen.

The outside is in the direction of the electric field and since the charge is negative, the force is directed INTO THE SCREEN

c) positive charge moves down

in magnetic field points up

in this case the velocity and the field have the same direction so the vector product of them is zero

F = q v B sin 0

F = 0

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3 years ago