Answer: ±√2
Step-by-step explanation: A fraction is undefined when its denominator is =0 or undefined. so we need to get 2/3x²-6=0 or undefined. so we can also do 3x^2-6=0. Solving yields ±√2!
M<1 = 1/2(b-d)
answer is C. third choice

From the diagram, we can see that the radius of the cone is 8cm and the height of the cone is 15cm. We then just plug these numbers into the formula and simplify:

The volume of the cone is approximately 1005.3096 cm^3. With 3 sig figs, this is 1010 cm^3.
84j is the equivalent.
Just add 36 to 48 and put the j on.
Answer: D) 101
Step-by-step explanation:
By linearity, we can break it up into 2 integrals. The integral and derivative of f easily cancel out

I used the table for values of f(x) at 10 and -1. Wouldn't be surprised if this was part of a series of questions about f because I really can't see how you could use the hypothesis that f is twice differentiable on R. Same for the other table values. I'm curious about how you found the answer. Was it a different way?