All categories

2 years ago

Which equation is parallel to the graph of y = 2x-5 and goes through the point (3,9)?

Mathematics

1 answer:

lawyer [7]2 years ago

6 0

Answer:

y = 2x + 3

Step-by-step explanation:

the slope is 2 so the line parallel will have a slope of 2

y-9 = 2(x-3)

y-9= 2x - 6

y = 2x +3

You might be interested in

Evaluate 5x-7 when x=2

Reptile [31]

Answer:

the answer is 3since x is 2 so it becomes 5times 2 minus 7 equals to 3

4 0

1 year ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

Graph the data below and then answer the questions that follow. year 1=$20,000, year 2=$21,750, year 3=$23,500, year 4=$25,250,

Mariana [72]

Answer:

Since the difference between the value for each year is constant, this is an arithmetic sequence.

Step-by-step explanation:

Year 2 - Year 1 = 21,750 - 20,000 = 1,750

Year 3 - Year 2 = 23,500 - 21,750 = 1,750

Year 4 - Year 3 = Year 5 - Year 4 = 1,750

3 0

2 years ago

Using the relationships between

Pavlova-9 [17]

Answer:

They will always intersect at one point

Step-by-step explanation:

6 0

1 year ago

Dexter plans and records his spending. In the coordinate

Marrrta [24]

Answer:

<h2><u><em>mark me as brilliant ~_~</em></u></h2>

Step-by-step explanation:

5 0

2 years ago