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IrinaVladis [17]
3 years ago
15

20 POINTS!! What would be the first step to solve this equation?

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

its b

Step-by-step explanation:

because you always have to divide by the number on top

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(4, 11), (10, 11), and (9, 7) is reflected over the y-axis .<br> PLEASE HELP THIS IS DUES TO DAY
maks197457 [2]

Answer:

The new coordinates would be (-4, 11)

(-10, 11) (-9, 7) Hope this helps!

8 0
3 years ago
What is the GCF of two prime Numbers ??Give an example.
Dima020 [189]
Since prime numbers only have two factors (itself and 1) then it would have to be the same number. So it would be the number besides one. Ex. Prime number: 7, the GCF would be 7 if it was compared with itself.
8 0
4 years ago
The ratio of boys to girls in Jamal's class is 3:2. If four more girls join the class, there will be the same number of boys and
olchik [2.2K]

Answer:

12 boys

Step-by-step explanation:

From the above question:

Number of boys = 3

Number of girls = 2

Boys: Girls

3:2

Let :

a = boys

b = girls

Hence, a : b = 3 : 2

a/b = 3/2  

Cross Multiply

2a = 3b .......... Equation 1

a = 3b/2

If four more girls join the class, there will be the same number of boys and girls

Hence,

a: b + 4 = 3 : 3

a/b + 4 = 3/3

Cross Multiply

3a = 3(b + 4)

3a = 3b + 12 ........ Equation (2)

From Equation 1: a = 3b/2

Substitute 3b/2 for a in Equation 2 we have:

3a = 3b + 12 .........Equation 2

3(3b/2) = 3b + 12

9b/2 = 3b + 12

Cross Multiply

9b = 2(3b + 12)

9b= 6b + 24

9b - 6b = 24

3b = 24

b = 8

Substitute 8 for b in Equation 1

a = 3b/2

a = 3 × 8/2

a = 24/2

a = 12

Therefore, the number of boys in the class is 12

7 0
3 years ago
Question in picture<br><br>A) 16/63<br><br>B)-16/63<br><br>C) 63/16<br><br>D) -63/16
Orlov [11]
ANSWER
\tan(x + y) =  -  \frac{63}{16}


EXPLANATION


We were given that,

\csc(x)  =  \frac{5}{3}

This implies that,

\sin(x)  =  \frac{3}{5}

We use the Pythagorean identity

\sin^{2} (x)  +  \cos^{2} (x)= 1
to get,


\cos(x)  =  \sqrt{1 - ( { \frac{3}{5} })^{2}}  =  \frac{4}{5}


We were also given that,


\cos(y)  =  \frac{5}{13}

This means that,


\sin(y)  =  \sqrt{1 -  {( \frac{5}{13}) }^{2} }  =  \frac{12}{13}

This is because,


0 <  \: x \:  <  \frac{\pi}{2}


0 <  \: y \:  <  \frac{\pi}{2}

This angles are in the first quadrant so we pick the positive values.

\tan(x + y)  =  \frac{ \sin(x + y) }{ \cos(x + y) }


\tan(x + y)  =  \frac{ \sin(x ) \cos(y)   +  \sin(y)  \cos(x) }{ \cos(x) \cos(y)  -  \sin(x)  \sin(y) }



\tan(x + y)  =  \frac{  \frac{3}{5}   \times  \frac{5}{13}  +   \frac{12}{13}   \times  \frac{4}{5}  }{  \frac{4}{5}  \times  \frac{5}{13}   -   \frac{3}{5}  \times  \frac{12}{13}  }



\tan(x + y) =  -  \frac{63}{16}

The correct answer is D
4 0
3 years ago
Can someone please answer this!!<br> Please only answer if you no!!
Alenkasestr [34]

Answer:

36

Step-by-step explanation:

5 0
3 years ago
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