Question

Kent has a collection of pennies and nickels with a value of 1.98$. the number of pennies he has is five less than twice the number of nickels. how many of each coin does Kent have?
1 define your variables ,- what are you solving for
2 set up equations - using the information given
3 solve the system using your method of choice

Answer 1

Kent has a collection of pennies and nickles with a value of $1.98. The number of pennies he has is five less than twice the number of nickles. How many of each coin does Kent have?
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p + 5n = 198
p = 2n - 5
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Sub for p
2n-5 + 5n = 198

Answer 2

Answer with Step-by-step explanation:

We are given that:

• Kent has a collection of pennies and nickels with a value of 1.98$.

• The number of pennies he has is five less than twice the number of nickels.  

1. Let p be the number of pennies

and n be the number of nickles

2. Then, p=2n-5

1 pennie=$0.01

1 nickle=$0.05

0.01p+0.05n=1.98

Multiplying both sides by 100,we get

p+5n=198

3. Putting p=2n-5 in p+5n=198,we get

2n-5+5n=198

7n=198+5

7n=203

n=29

Putting value of n in p=2n-5, we get

p=2×29-5

p= 58-5

p= 53

Hence, Number of pennies=53

and number of nickle=29