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hram777 [196]
3 years ago
10

Lisa wrote the expression (3x + 6x) - 2(x + 1) + 5. She simplified the expression using the following steps:

Mathematics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The given expression is : (3x + 6x) - 2(x + 1) + 5

In very first step,  Lisa made a mistake.

Lisa took 3 as common factor out and what she wrote is 3 (1+x) but when she took 3 as common factor, the expression would be 3 (x+2x)

Here she made a mistake.

3(x+2x)-2(x+1)+5

9x-2(x+1)+5

9x-2x-2+5

7x+3

So, the correct answer is 7x+3  :   Answer

Hope it willhelp :)

Ivanshal [37]3 years ago
6 0

Answer:

Step 1. Should be 3(x +2x) -2(x +1) +5 . . .

or . . . 3x(1 +2) -2(x +1) +5 . . .

or . . . 9x -2(x+1) +5

Step-by-step explanation:

Lisa apparently failed to realize that both terms inside the first set of parentheses have 3x as a factor. They are like terms, so could be combined directly. If Lisa really wants to factor out 3 or 3x, she could do so and then combine the remaining factors at another step.

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Rita = $150

Bob = $150 - $35 = $115    Bob has $115

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3 years ago
X=3816371/(27×63) solve for x
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Answer:

X = 14,700

Step-by-step explanation:

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A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

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Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

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Roman55 [17]

Answer:

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Step-by-step explanation:

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