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3 years ago

What is the slope of a line that is perpendicular to the line whose equation is ax+by=c?

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

The perpendicular line will have a slope of b/a.

To find this, we first have to solve our equation for slope intercept form.

ax + by = c ----> subtract ax

by = -ax + c ----> divide by b

y = -a/bx + c/b.

So we know the slope of this equation to be -a/b. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of b/a.

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If you answer this ill give u brainliest what is 23*45*98-3

nikdorinn [45]

(23*45*98)-3 = 101,427

the answer is = 101,427

23*45 = 1,035

1,035*98 = 101,430

101,430 - 3 = 101,427

7 0

3 years ago

Can someone help with the two triangle questions (will mark brainliest!!)

yaroslaw [1]

Answer: Number 1 is c=89 ft

Number 2 is b=3 cm

Step-by-step explanation: a²+b²=c²

For number 1, 39 ft is a and 80 ft is b so

39²+80²=c² so 39² is 39x39=1521 and 80² is 80x80=6400 so 6400+1521=7921

7921=c² and the square root of 7921 is 89 so c=89 ft

For number 2, a=1.6 cm and c=3.4 cm so 3.4²-1.6²=b²

3.4² so 3.4x3.4 which is 11.56

1.6² so 1.6x1.6 which is 2.56

11.56-2.56=c² and 11.56-2.56=9

Square root of 9 is 3 so b=3

So number 2 answer is b=3 cm

I hope this helps

4 0

3 years ago

Given the figure below, find the values of x and z.

charle [14.2K]

Answer:

I think z = 89 and I don’t know x

8 0

3 years ago

25 is 45% of what number

Oksi-84 [34.3K]

Answer: 55.56

Step-by-step explanation:

Let the unknown number be k

(45 x k) / 100 = 25

45k/100 = 25

multiply both sides by 100

45k = 25 x 100

45k = 2500

divide both sides by 45

k = 2500/45

k = 55.56

6 0

3 years ago

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

6 0

3 years ago