Answer:
V≈628.32
Step-by-step explanation:
The value of p if the pair of equations may have one root common is 1.
<h3>What are the
roots of the equation?</h3>
Let the equation be ax² + bx + c = 0.
Then the roots of the equation will be

The equations are given below.
2x² + px - 1 = 0 and 3x² - 2x - 5 = 0
The roots of the equation 3x² - 2x - 5 = 0 will be
3x² - 5x + 3x - 5 = 0
(3x - 5)(x + 1) = 0
x = -1, 5/3
At x = -1, the value of p will be
2(-1)² + p(-1) - 1 = 0
2 - p - 1 = 0
p = 1
The value of p if the pair of equations may have one root common is 1.
More about the roots of the equation link is given below.
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As far a domain, you only care about the denominator and radicals.
f(x) = 2 - √x is the denominator, so it can't be 0.
Also x is under a radical, so x can't be negative.
Set the denominator equal to 0 to find the excluded values.
2 - √x = 0
-√x = -2
√x = 2
x = 4, so 4 is an excluded value
The domain is all real numbers greater than or equal to 0, except 4.
[0, 4) U (4, ∞)
0 ≤ x < 4 U x > 4
In geometry, the length of JK in terms of a, b, and x will be D. abx
<h3>How to illustrate the information?</h3>
It should be noted that from the information given, it was stated that in circle M, EMF measures the radians allocated, the length of radius FM is and the length of EF is x.
In the other circle, JNK also measures the radians allocated and the length of radius KN is b.
Therefore, the length of JK in terms of a, b, and x will be:
= a × b × x
= abx
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Answer:
The answer is 35/3. I hope it helps you....