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4 years ago

Equivalent expression of y5/y8

Mathematics

1 answer:

Trava [24]4 years ago

3 0

Answer:

1/y3

Step-by-step explanation:

divide y5 on top

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so

allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> $y+12=x^{2}+x$ and $x+y=3$

Part 2) No solutions ----> $y-15=x^{2}+4x$ and $x-y=1$

Part 3) solution [(-2,5),(3,-5)] ---> $y+5=x^{2}-3x$ and $2x+y=1$

Part 4) No solutions ---> $y-6=x^{2}-3x$ and $x+2y=2$

Part 5) solution [(2,3),(8,9)] ---> $y-17=x^{2}-9x$ and $-x+y=1$

Part 6) solution [(-2,3),(7,-6)] ---> $y-15=-x^{2}+4x$ and $x+y=1$

Step-by-step explanation:

Part 1) we have

$y+12=x^{2}+x$ ----> equation A

$x+y=3$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)

see the attached figure N 1

Part 2) we have

$y-15=x^{2}+4x$ ----> equation A

$x-y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 2

Part 3) we have

$y+5=x^{2}-3x$ ----> equation A

$2x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)

see the attached figure N 3

Part 4) we have

$y-6=x^{2}-3x$ ----> equation A

$x+2y=2$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 4

Part 5) we have

$y-17=x^{2}-9x$ ----> equation A

$-x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)

see the attached figure N 5

Part 6) we have

$y-15=-x^{2}+4x$ ----> equation A

$x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)

see the attached figure N 6

5 0

3 years ago

8) The equation of a line that has a slope of -2 and a y-intercept of 3 is:

Eva8 [605]

The bb and j was the source of the questions

5 0

3 years ago

What is the answer to this 8-(-8)=

Komok [63]

Answer:

Step-by-step explanation:

the two negatives cancel out so if you are subtracting -8 from 8 you would actually end up adding them.

hope it helps!

5 0

3 years ago

Read 2 more answers

Please please help me please

MAVERICK [17]

Answer:

1st option is the answer

Step-by-step explanation:

blue line: slope is 1 and y-intercept is 1; therefore equation is y= x + 1

red line: slope is -1 and y-intercept is -3; therefore equation is y= -x - 3

7 0

3 years ago

Is the point (1,5) a solution to the equation below?

allochka39001 [22]

Answer:

A. No

Step-by-step explanation:

y = 2x + 4

(5) = 2(1) + 4

5 = 2 + 4

5 = 6 (false statement)

7 0

3 years ago