Answer:
same as the answer of her
Explanation:
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Answer:
19.8 kg of C₂H₂ is needed
Explanation:
We solve this by a rule of three:
If 1251 kJ of heat are relased in the combustion of 1 mol of acetylene
95.5×10⁴ kJ of heat may be released by the combustion of
(95.5×10⁴ kJ . 1) /1251kJ = 763.4 moles of C₂H₂
Let's convert the moles to mass → 763.4 mol . 26 g/1 mol = 19848 g
If we convert the mass from g to kg → 19848 g . 1kg / 1000g = 19.8 kg
Mmm, you can work this one out in your head by reversing it.
<span>12.5 = 50g/4 </span>
<span>1/4 = 1/2 * 1/2 </span>
<span>thus in 14.4 seconds there have been 2 times the half life. 14.4/2 = 7.2 </span>
<span>the half life is 7.2 seconds.</span>
Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
Solution : Given,
Solubility of a gas in water = 1.22 g/L (at 2.75 atm pressure)
At pressure = 1 atm, Solubility of a gas = ?
Now we have to calculate the solubility of a gas.
At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L
At 1 atm pressure, the solubility of a gas in water =
Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
Answer:
We might just have to end it together
Explanation:
I tried to answer it now I'm stuck in the same hole -_-