Explanation:
The sum of all oxidation numbers in a neutral compound is zero. The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion. The oxidation number of oxygen in a compound is usually –2. The oxidation state of hydrogen in a compound is usually +1.
The oxidation state of Al in Al(OH)
4
−
x+4(+1−2)=−1
∴x=+3
The oxidation state of Mn in MnO
2
y+2(−2)=0
∴y=+4
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Alcohol is a pure substance
Answer:
0.46 V
Explanation:
The emf for the cell is given by:
Eº cell = Eº oxidation + Eº reduction
From the given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced from 0 to negative 2, according to the half cell reactions:
4Fe²⁺ ⇒ Fe³⁺ + 4e⁻ oxidation
O₂ + 4H⁺ + 4 e⁻ ⇒ 2 H₂O reduction
From reference tables for the standard reduction potential, we get
Eº red Fe³⁺ / Fe²⁺ Eºred = 0.77 V
Eº red O₂ / H₂O Eºred = 1.23 V
Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction O₂:
Eº cell = Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V
Answer:
Sn₃(PO₄)₄ - tin(IV) phosphate.
Explanation:
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Answer:
Explanation:
Translated:
Calculate the amount of sugar (C12 H22 O11) in the morning tea if a teaspoon contains 5g of sugar?
Given parameters
Mass of sugar = 5g
Unknown:
Amount of the sugar =?
Solution:
A mole is the amount of substance that contains avogadro's number of particles i.e 6.02 x 10²³
Therefore, to find the number of moles contained in the teaspoon of sugar we use the expression below:
Number of moles = 
Molar mass of C₁₂H₂₂O₁₁ = (12x12) + (1x22) + (16x11) = 342g/mol
Number of moles = 
= 0.015mol of sugar
or 0.015 x 6.02 x 10²³, 8.8x10²¹atoms of sugar
