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krek1111 [17]
3 years ago
9

Help pls before I end it all

Chemistry
2 answers:
qwelly [4]3 years ago
7 0

Answer:

We might just have to end it together

Explanation:

I tried to answer it now I'm stuck in the same hole -_-

Dmitrij [34]3 years ago
5 0
Ok so for every 8 miles of NHO3 you can make 4 moles of water

So 70 moles of NHO3 can give you 70/8*4=35 moles of water
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What do strong and weak acids have in common?
Natali5045456 [20]

Answer:

All the above

Explanation:

A. Electrical current conduction

Aqueous solutions of both strong and weak acids will conduct an electric current. Weak acids are poorer conductors because they produce fewer ions.

B. Reaction with magnesium

Both strong and weak acids will react with magnesium, although weak acids will react more slowly.

C. pH paper test

Both strong and weak acids will give a colour with pH test paper, although the colours will probably be different.

D. Litmus paper test

Both strong and weak acids will turn blue litmus red.

4 0
4 years ago
Read 2 more answers
Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa = 4.874) using the symbols HA and A–, an
Luden [163]
The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
pH = pKa + log([base]/[acid]), where the brackets imply concentrations
Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
7 0
3 years ago
The heat change that accompanies the formation of 1.00 mol of carbon dioxide from its elements is −393.7 kJ/mol. What heat chang
gladu [14]

Answer:

-248.425 kJ/mol

Explanation:

This question can be done by simply taking the ratios:

Since the given the heat change for 1.00 mol of CO_2 is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of

We can write:

\frac{-373.7} {1.00} = \frac{x}{0.631}

x = ( -373.7)(0.631)

x = -248.425 KJ/mol

7 0
3 years ago
1.2m^3 = _________yd^3
jek_recluse [69]

1.57yd³

Explanation:

This is a conversion problem from m³ to yd³;

   Given 1.2m³, convert to yd³

    1m = 1.094yd

We are going to use a conversion factor of 1 to solve this problem;

   m³ = m x m x m

1.2 m ³ =   1.2 x m x m x m x \frac{1.094yd}{1m}   x   \frac{1.094yd}{1m}     x    \frac{1.094yd}{1m}

          = 1.57yd³

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

6 0
3 years ago
What will litmus paper turn when it reacts with sodium nitrate?​
castortr0y [4]
A solution of sodium nitrate will get make litmus paper wet. A solution of NaNO3 is neutral. Therefore, there is no change in color.
6 0
3 years ago
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