- The mass percent of
Pentane in solution is 16.49%
- The mass percent of
Hexane in solution is 83.51%
<u>Explanation</u>:
- Take 1 kg basis for the vapor: 35.5 mass% pentane = 355 g pentane with 645 g hexane.
-
Convert these values to mol% using their molecular weights:
Pentane: Mp = 72.15 g/mol -> 355g/72.15 g/mol = 4.92mol
Hexane: Mh = 86.18 g/mol -> 645g/86.18 g/mol = 7.48mol
Pentane mol%: yp = 4.92/(4.92+7.48) = 39.68%
Hexane mol%: yh = 100 - 39.68 = 60.32%
Pp-vap = 425 torr = 0.555atm
Ph-vap = 151 torr = 0.199atm
-
From Raoult's law we know:
Pp = xp 
Pp - vap = yp Pt (1)
Ph = xh Ph - vap = yh Pt (2)
-
Since it is a binary mixture we can write xh = (1 - xp) and yh = (1 - yp), therefore (2) becomes:
(1 - xp) Ph - vap = (1 - yp) Pt (3)
-
Substituting (1) into (3) we get:
(1-xp) Ph - vap = (1 - yp) xp Pp - vap / yp (4)
xp = Ph - vap / (Pp - vap/yp - Pp - vap + Ph - vap) (5)
-
Subbing in the values we find:
Pentane mol% in solution: xp = 19.08%
Hexane mol% in solution: xh = 80.92%
-
Now for converting these mol% to mass%, take 1 mol basis for the solution and multiplying it by molar mass:
mp = 0.1908 mol 72.15 g/mol
= 13.766 g
mh = 0.8092 mol 86.18 g/mol
= 69.737 g
-
Mass% of Pentane solution = 13.766/(13.766+69.737)
= 16.49%
-
Mass% of Hexane solution = 83.51%
Answer:
It's just asking you to rearrange to equations to get what you want, so no numbers involved it's just teaching you the basics.
Explanation:
Potassium is fundamental for neuron activity. If a body does not have enough potassium, then the neuron will struggle to fire because there will not be enough positively charged ions to trigger the firing of the neuron.
The potassium (K+) is maintained at a high level within the neuron at rest, whereas sodium (Na+) is maintained at a high level outside of the cell.
Neurons contain K+ and Na+ leakage channels that allow the two ions to diffuse in favor of a concentration gradient.
Depolarization opens both K+ and Na+ channels in the membrane, thereby these ions can flow out and into the axon, respectively.
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Answer:
3.98×10⁻¹⁹ J
Explanation:
Applying,
E = hf................. Equation 1
Where E = energy of the photon, h = planck's constant, f = frequency of the photon
From the question,
Given: f = 6.00×10¹⁴ Hz
Constant: h = 6.626×10⁻³⁴J.s
Substitute these values into equation 1
E = (6.00×10¹⁴)(6.626×10⁻³⁴)
E = 39.756×10⁻²⁰
E = 3.98×10⁻¹⁹ J
Hence the energy of the photon in joules is 3.98×10⁻¹⁹ J
