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lesya692 [45]
3 years ago
6

If the solubility of a gas in water is 1.22g/2.75 atm, what is it’s solubility (in g/L) at 1.0 atm

Chemistry
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L

Solution : Given,

Solubility of a gas in water = 1.22 g/L     (at 2.75 atm pressure)

At pressure = 1 atm,     Solubility of a gas = ?

Now we have to calculate the solubility of a gas.

At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L

At 1 atm pressure, the solubility of a gas in water = \frac{1atm}{2.75atm}\times 1.22g/L=0.4436g/L

Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L


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Answer:

b. The number of electrons

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A "neutral atom" has a <u>neutral charge</u>. This means that <em>its charge is equal to </em><em>zero. </em>In order for the charges to cancel out each other, the atom's <em>positive charge should be equal to the negative charge. </em>These being said, the number of electrons<em> (negatively-charged)</em> is then equal to the number of protons <em>(positively-charged). </em>Those atoms which are not neutral are called <em>"ions."</em> This means that they either have more or less electrons than the protons.

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quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe
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After 25 days, it remains radon 5.9x10^5 atoms.

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t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

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The half-life is independent of initial concentration (size of the sample).

More about half-life: brainly.com/question/1160651

#SPJ4

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For the reaction 6 Li + N2 → 2 Li3N , what is the maximum amount of Li3N (34.8297 g/mol) which could be formed from 14.18 mol (6
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Moles Li = 3.50 g / 6.941 g/mol= 0.504
the ratio between Li and N2 is 6 : 1
moles N2 required = 0.504 /6=0.0840
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mass Li3N = 0.168 mol x 34.8297 g/mol=5.85 g
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