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lesya692 [45]
3 years ago
6

If the solubility of a gas in water is 1.22g/2.75 atm, what is it’s solubility (in g/L) at 1.0 atm

Chemistry
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L

Solution : Given,

Solubility of a gas in water = 1.22 g/L     (at 2.75 atm pressure)

At pressure = 1 atm,     Solubility of a gas = ?

Now we have to calculate the solubility of a gas.

At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L

At 1 atm pressure, the solubility of a gas in water = \frac{1atm}{2.75atm}\times 1.22g/L=0.4436g/L

Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L


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A substance that can be broken down and recycled by bacteria and other decomposes is said to be__________
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Answer:The substance is Biodegradable

Explanation:

When something is biodegradable it can be broken down by organical processes or decomposers.

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Incomplete dash of fuels produces many poisonous dash​
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3 years ago
Draw the Lewis dot structure for RbIO2. Include all hydrogen atoms and nonbonding electrons. Show the formal charges of all atom
Rzqust [24]

Answer : The Lewis-dot structure of RbIO_2  is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, RbIO_2

As we know that rubidium has '1' valence electrons, iodine has '7' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in RbIO_2 = 1 + 7 + 2(6) = 20

As we know that RbIO_2  is an ionic compound because it is formed by the transfer of electron takes place from metal to non-metal element.

7 0
3 years ago
A student estimated the volume of a liquid in a beaker as 200.0 mL. When she poured the liquid into a graduated cylinder she MEA
Taya2010 [7]

Answer:

<h3>The answer is 0.91 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 198.2 mL

error = 200 - 198.2 = 1.8

So we have

P(\%) =  \frac{1.8}{198.2}  \times 100 \\  = 0.90817356205...

We have the final answer as

<h3>0.91 %</h3>

Hope this helps you

6 0
3 years ago
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