All categories

3 years ago

If the solubility of a gas in water is 1.22g/2.75 atm, what is it’s solubility (in g/L) at 1.0 atm

Chemistry

1 answer:

Slav-nsk [51]3 years ago

5 0

Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L

Solution : Given,

Solubility of a gas in water = 1.22 g/L (at 2.75 atm pressure)

At pressure = 1 atm, Solubility of a gas = ?

Now we have to calculate the solubility of a gas.

At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L

At 1 atm pressure, the solubility of a gas in water = $\frac{1atm}{2.75atm}\times 1.22g/L=0.4436g/L$

Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L

You might be interested in

5. En el laboratorio se dispone de una disolución concentrada de ácido clorhídrico del 30% en masa y densidad 1.15g/cm3.Calcula:

tia_tia [17]

Answer:

the eye of the tiger in the bronx zoo tiger king meme with

4 0

3 years ago

Read 2 more answers

Why would heating up the human body be a bad choice for causing a chemical reaction?

Furkat [3]

Answer:

Explained below

Explanation:

The human body has a normal core temperature of around 37°C to 38°C.

Now, if it is heated up to say 39° to 40°C, fatigue will start to set in and the brain begins to tell the muscles to slow down.

If it's now heated to higher temperatures above above 41°C, the body will begin to experience heat exhaustion and therefore will start to shut down.

Due to this process, the body can't even sweat at that stage because blood flow to the skin will stops thereby making the body feel cold and clammy. Thus, chemical processes/reaction in the body will begin to be affected and the cells inside the body will start to deteriorate and thus there is now a huge risk of having multiple organ failure.

5 0

3 years ago

Consider the Gibbs energies at 25 ∘C.

zysi [14]

Answer:

A)ΔGrxn∘=55.7kJ/mol

B)Ksp=1.75×10^−10

C)ΔGrxn∘=70.0kJ/mol

D)Ksp=5.45×10^−13

Explanation:

ΔGrxn∘=ΔGf,products∘−ΔGf,reactants∘

To calculate for the

Ksp

of the dissolution reaction can be claculated

ΔGrxn∘=−RTlnKsp

where R is the proportionality constant equal to 8.3145 J/molK.

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Cl(aq)−∘]−ΔGf,

AgCl(s)⇌Ag(aq)++Cl(aq)−

ΔG∘rxn=[77.1kJ/mol+(−131.2kJ/mol)]−(−109.8kJ/mol)

ΔGrxn∘=55.7kJ/mol

b) Calculate the solubility-product constant of AgCI.

ΔGrxn∘=−RTlnKsp

55.7kJ/mol=−(8.3145×10−3J/molK)(298.15K)InKsp

Ksp=1.75×10^−10

c) Calculate

To calculate ΔG°rxn

for the dissolution of AgBr(s).

ΔGrxn∘=[ΔGf,Ag(aq)+∘+ΔGf,Br(aq)−∘]−ΔGf,

ΔGrxn∘=[77.1kJ/mol+(−104.0kJ/mol)]−(−96.90kj/mol

ΔGrxn∘=70.0kJ/mol

d)To Calculate the solubility-product constant of AgBr.

ΔGrxn∘=−RTlnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K)lnKsp

70.0kJ/mol=−(8.3145×10−3J/molK)(298.15K

Ksp=5.45×10^−13

8 0

3 years ago

The following is what kind of reaction? 2 CH4 +4 02 → 2 CO2 + 4H2O

zepelin [54]

Answer:

It is a combustion reaction.

5 0

3 years ago

Which pair of compounds has the same empirical formula? c3h8 and c3h c2h2 and c2h c4h10 and c6h c4h10 and c2h5.

BartSMP [9]

Answer:

The correct answer is the final pair: C4H10 and C2H5

Explanation:

Took the test and it was right. :)

8 0

3 years ago