Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
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Answer:
3(3x-1)
Step-by-step explanation:
3(2x-1)+3
3(2x-1x)
3(3x-1)
3(3x-1)
The answer is c (4, 1) because when you add 1 to the x value it moves right one and then when you subtract 3 from the y value it goes down 3 making it (4, 1)
The answer is 3.48 < (with the line under) x
6v = 5/8+ 7/8
6v= 12/8
6v=6/4 = 3/2
V= (3/2)/6
V=(3/2) • (1/6)
V= 3/12
V = 1/4
