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2 years ago

3y-6 divided by 9 = 4-2 divided by -3

Mathematics

2 answers:

antoniya [11.8K]2 years ago

4 0

I believe the answer is 16/9

Sergeeva-Olga [200]2 years ago

4 0

Y=4/3 hope this helps

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This question is kind of confusing and i need help, please and thank you! :)

solong [7]

ummmmmmmm a lot and alot

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2 years ago

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The diagram below shows a square inside a regular octagon. The apothem of the octagon is 15.69 units. To the nearest square unit

Musya8 [376]

Answer:

C. 647 square units

Step-by-step explanation:

To find the shaded area, subtract the area of the unshaded square from the area of the octagon.

Area of the octagon

$\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}$

where:

n = number of sides
l = length of one side
a = apothem

Given:

n = 8
l = 13
a = 15.69

Substitute the given values into the formula and solve for A:

$\implies \textsf{Area}=\sf \dfrac{8 \cdot 13 \cdot 15.69}{2}$

$\implies \textsf{Area}=\sf \dfrac{1631.76}{2}$

$\implies \textsf{Area}=\sf 815.88\:\:square \:units$

Area of the square

$\implies \textsf{Area}=\sf 13^2=169 \:\:square \:units$

Area of the shaded region

= area of the octagon - area of the square

= 815.88 - 169

= 646.88

= 647 square units (nearest square unit)

3 0

2 years ago

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What is equivalent to 4:3

kap26 [50]

Answer:

the answer is 6:8 or 9:12

Step-by-step explanation:

7 0

2 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago

A single die is rolled. Find the probability of rolling an oddnumber or a number less than 6.

mina [271]

Given

A single die is rolled.

To find the probability of rolling an odd number or a number less than 6.

Explanation:

It is given that,

A single die is rolled.

Then, the sample space is,

$\begin{gathered} S=\lbrace1,2,3,4,5,6\rbrace \\ n(S)=6 \end{gathered}$

Let A be the event of getting an odd number.

Then,

$\begin{gathered} A=\lbrace1,3,5\rbrace \\ n(A)=3 \end{gathered}$

Let B be the event of getting a number less than 6.

Then,

$\begin{gathered} B=\lbrace1,2,3,4,5\rbrace \\ n(B)=5 \end{gathered}$

Also,

$\begin{gathered} A\cap B=\lbrace1,3,5\rbrace \\ n(A\cap B)=3 \end{gathered}$

Therefore,

$\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{n(A\cap B)}{n(S)} \\ =\frac{3}{6}+\frac{5}{6}-\frac{3}{6} \\ =\frac{3+5-3}{6} \\ =\frac{5}{6} \end{gathered}$

Hence, the answer is 5/6.

5 0

11 months ago

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