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krok68 [10]
2 years ago
9

Convert to the unit in brackets

Mathematics
1 answer:
IRINA_888 [86]2 years ago
6 0

Step-by-step explanation:

<em>4</em><em> </em><em>ton</em><em> </em><em>in</em><em> </em><em>kg</em><em> </em><em>=</em><em>4</em><em>×</em><em>1</em><em>0</em><em>0</em><em>0</em><em>=</em><em>4</em><em>0</em><em>0</em><em>0</em><em>k</em><em>g</em>

<em>5</em><em> </em><em>kg</em><em> </em><em>in</em><em> </em><em>ton</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em>1</em><em>0</em><em>0</em><em>0</em><em>=</em><em>5</em><em>0</em><em>0</em><em>0</em><em>k</em><em>g</em>

<em>6</em><em>=</em><em>kg</em><em> </em><em>=</em><em>6</em><em>×</em><em>1</em><em>0</em><em>0</em><em>0</em><em>=</em><em>6</em><em>0</em><em>0</em><em>0</em><em>k</em><em>g</em>

<em>7</em><em>m</em><em>m</em><em> </em><em>in</em><em> </em><em>cm</em><em> </em><em>=</em><em> </em><em>7</em><em>×</em><em>1</em><em>0</em><em>=</em><em>7</em><em> </em><em>cm</em>

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).
spayn [35]

The Bernoulli distribution is a distribution whose random variable can  only take 0 or 1

  • The value of E(x2) is p
  • The value of V(x) is p(1 - p)
  • The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * (1- p) + 1^2 * p

Evaluate the exponents

E(x^2) = 0 * (1- p) + 1 * p

Multiply

E(x^2) = 0 +p

Add

E(x^2) = p

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Start by calculating E(x) using:

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * (1- p) + 1 * p

E(x) = p

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = p - p^2

Factor out p

V(x) = p(1 - p)

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

E(x^{79}) = \sum x^{79} * P(x)

So, we have:

E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p

Evaluate the exponents

E(x^{79}) = 0 * (1- p) + 1 * p

Multiply

E(x^{79}) = 0 + p

Add

E(x^{79}) = p

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0
2 years ago
Which expression has a value of 15 when n = 7?
sweet [91]
The answer is D.

Explanation- 28/7=4

19-4 =15
6 0
3 years ago
Standard form of a line that has a slope of -1 and passes through (-5,-1)
Anestetic [448]

Step-by-step explanation:

y + 1 = -(x+5)

y + 1 = -x - 5

y = -x - 6

x + y = -6

3 0
3 years ago
The weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 l
joja [24]

1. Know what you're looking for:

The range is the difference between the lowest and highest values.

Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.


2. Calculate your lowest and highest values :


Lowest : 145.2 - 0.3 = 144.9 lbs

Highest : 145.2 + 0.3 = 145.5 lbs


3. Calculate the range of actual weights of the object :


145.5 - 144.9 = 0.6 lbs


--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>


There you go! I really hope this helped, if there's anything just let me know! :)

4 0
3 years ago
6=p*36. <br><br> **HINT** 17% IS NOT THE ANSWER AS TESTED!
grin007 [14]
Divide both sides by 36
6/36 = p
1/6 = p
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3 years ago
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