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Otrada [13]
3 years ago
8

5

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

(h o k)(3)=  3

(K o h)(-4b)= - 4b

Step-by-step explanation:

Composition of a function and its inverse function returns the input

(h o k)(3)=  3

(K o h)(-4b)= - 4b

shusha [124]3 years ago
7 0

Answer:

(h\circ k)(3)=3

(k\circ h)(-4b)=-4b

Step-by-step explanation:

Remember that for two functions to be inverses, the following must be true:

h(k(x))=k(h(x))=x

Since we know they <em>are </em>indeed inverses, they are true.

So, whatever input we put in, we'll just get it back out again.

So, for our first problem:

(h\circ k)(3)

We can rewrite this as:

=h(k(3))

We can imagine our x being 3 here.

Therefore, using the above identity, we can conclude that:

h(k(3))=3

For our second example, the same thing:

(k\circ h)(-4b)

This is the same as saying:

k(h(-4b))

Again, using the above property, we can imagine our x is -4b. So, this will be equivalent to:

k(h(-4b))=-4b

And we're done!

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Answer:

= 3x - 3y

Step-by-step explanation:

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Graph the function y = 4x4 – 8x2 + 4. Which lists all of the turning points of the graph?
Serhud [2]

Answer:

4(x + 1)^{2}(x - 1)^{2}

Step-by-step explanation:

STEP 1:

The equation at the end of step 1

((4 (x^4)) -  2^3x^2) +  4

STEP 2:

The equation at the end of step 2:

(2^2x^4 -  2^3x^2) +  4

STEP 3:

STEP 4: Pulling out like terms

<u>4.1</u> Pull out like factors:

4x^4 - 8x^2 + 4  =   4(x^4 - 2x^2 + 1)

Trying to factor by splitting the middle term

<u>4.2</u> Factoring x^4 - 2x^2 + 1

The first term is, x^4 its coefficient is 1.

The middle term is,  -2x^2  its coefficient is -2.

The last term, "the constant", is +1.

Step-1: Multiply the coefficient of the first term by the constant   1 • 1 = 1

Step-2: Find two factors of  1  whose sum equals the coefficient of the middle term, which is -2.

-1 + -1 = -2 That's it

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  -1

                    x4 - 1x2 - 1x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x2 • (x2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (x2-1)

Step-5 : Add up the four terms of step 4 :

                   (x2-1)  •  (x2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

4.3      Factoring:  x2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Trying to factor as a Difference of Squares:

4.4      Factoring:  x2 - 1

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Multiplying Exponential Expressions:

4.5    Multiply  (x + 1)  by  (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x+1)  and the exponents are :

         1 , as  (x+1)  is the same number as  (x+1)1

and   1 , as  (x+1)  is the same number as  (x+1)1

The product is therefore,  (x+1)(1+1) = (x+1)2

Multiplying Exponential Expressions:

4.6    Multiply  (x-1)  by  (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x-1)  and the exponents are :

         1 , as  (x-1)  is the same number as  (x-1)1

and   1 , as  (x-1)  is the same number as  (x-1)1

The product is therefore,  (x-1)(1+1) = (x-1)2

Final result :

 4 • (x + 1)2 • (x - 1)2

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Answer:

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... 180° -90° -45° = 45°

The sides opposite these congruent angles are the same length, 14 km in this case, and the hypotenuse is found from the Pythagorean theorem to be √2 times either leg length.

... AB² = AC² +BC²

... AB = √(AC² +BC²) = (14 km)√(1² +1²) = 14√2 km

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To solve this polynomial equation, we will need to factor the left side.

On the left, we have a a trinomial in a special form that

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The trinomial on the left can be factored which makes life easier.

This factors as (x + 11)(x - 2) = 0.

This means that either x + 11 = 0 or x - 2 = 0.

Solving each equation from here, we get x = -11 or x = 2.

So the solution is {-11, 2}.

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