Question

5

Answer 1

Answer:

(h o k)(3)=  3

(K o h)(-4b)= - 4b

Step-by-step explanation:

Composition of a function and its inverse function returns the input

(h o k)(3)=  3

(K o h)(-4b)= - 4b

Answer 2

Answer:

$(h\circ k)(3)=3$

$(k\circ h)(-4b)=-4b$

Step-by-step explanation:

Remember that for two functions to be inverses, the following must be true:

$h(k(x))=k(h(x))=x$

Since we know they are indeed inverses, they are true.

So, whatever input we put in, we'll just get it back out again.

So, for our first problem:

$(h\circ k)(3)$

We can rewrite this as:

$=h(k(3))$

We can imagine our x being 3 here.

Therefore, using the above identity, we can conclude that:

$h(k(3))=3$

For our second example, the same thing:

$(k\circ h)(-4b)$

This is the same as saying:

$k(h(-4b))$

Again, using the above property, we can imagine our x is -4b. So, this will be equivalent to:

$k(h(-4b))=-4b$

And we're done!