Answer: 5th degree trinomial
The degree is 5 because its the largest exponent of the single variable polynomial.
It's a trinomial because there are 3 terms. The terms are separated by a plus or a minus.
In the given graph, lets mark two points:
Let 
and 
The slope of the line is given by:
The equation of the line is given by:
Therefore, the function equation represented by the graph is: 
Answer: Delete the point (0, 4)
<u>Step-by-step explanation:</u>
Your line for y = (1/3)x + 4 is correct.
m=1/3 b=4
Start at (0, 4) and draw a line through a point up 1 and 3 to the right (3, 5).
Your line for x = 6 is correct.
A vertical line through (6, 0), (6, 1), (6, 2), ...
Your point for (6, 6) is correct.
x=6, y=6
Your error is that you used the dot tool to plot a point for (0, 4). You DO need this point to create the line y = (1/3)x + 4, however the instructions do not state to mark this coordinate with a dot.
Answer:
13 and 65
Step-by-step explanation:
x + 5x = 78
(because u want a piece (x) and a piece that's five times longer than x- so 5x. and they should come from a 78 inch piece)
6x = 78
x = 78 / 6
x= 13
(to counter check: 13 * 5 = 65.
65 + 13 = 78 )
Answer:
Please check the explanation.
Step-by-step explanation:
Finding Domain:
We know that the domain of a function is the set of input or argument values for which the function is real and defined.
From the given graph, it is clear that the starting x-value of the line is x=-2, the closed circle at the starting value of x= -2 means the x-value x=-2 is included.
And the line ends at the x-value x=1 with a closed circle, meaning the ending value of x=1 is also included.
Thus, the domain is:
D: {-2, -1, 0, 1} or D: −2 ≤ x ≤ 1
Finding Range:
We also know that the range of a function is the set of values of the dependent variable for which a function is defined
From the given graph, it is clear that the starting y-value of the line is y=0, the closed circle at the starting value of y = 0 means the y-value y=0 is included.
And the line ends at the y-value y=2 with a closed circle, meaning the ending value of y=2 is also included.
Thus, the range is:
R: {0, 1, 2} or R: 0 ≤ y ≤ 2
