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3 years ago

10

On Monday Charlie earned $16 for 2 hours of babysitting. Getting paid the same rate he earned $40 for babysitting on Saturday Ho

w many hours did Charlie babysit on Saturday?

2 answers:

Vlada [557]3 years ago

8 0

5 hours. 16 divided by 2 equals 8 40 divided b 8 equals 5

hichkok12 [17]3 years ago

6 0

He Had Babysit For 05 Hours . ( Don't Forget To Add Me & Say Thank Youu ❤️ )

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27 1/5 over 4/5 as a unit rate

REY [17]

Answer:

$\frac{34}{1}$ or $34$

Step-by-step explanation:

we know that

To find the unit rate divide 27 1/5 by 4/5

but first

Convert mixed number to an improper fraction

$27\frac{1}{5}=27+\frac{1}{5}=\frac{27*5+1}{5} =\frac{136}{5}$

so

$\frac{136}{5}:\frac{4}{5}=\frac{136}{4}=\frac{34}{1}$

8 0

2 years ago

Rewrite 14 1/3 as an improper fraction

Anastaziya [24]

Answer:

Step-by-step explanation:

((14×3) + 1 )/3 = (43/3)

5 0

2 years ago

A lawn care company sells grass seed by the pound. There is one price per pound up to 5 pounds and a lower price per pound for e

VashaNatasha [74]

Answer:

I think its C

Step-by-step explanation:

5 0

2 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago

Jesse made a model of a mountain range for class. to do this, he bought a cylinder of cardboard and cut it into three cones. eac

aniked [119]

By definition, the volume of the cone is given by:
V = (1/3) (π) (r ^ 2) (h)
Substituting values we have:
V = (1/3) (π) ((4/2) ^ 2) (5)
V = (20/3) (π)
Then, the volume of the cylinder is:
Vc = 3 * V
Vc = 3 * (20/3) (π)
Vc = 20π
Answer:
the volume of the original cylinder jesse bought is:
Vc = 20π

4 0

3 years ago