There are 10 hydrogen atoms that bind and there are 2 pairs of free electrons in the non-binding O atom
<h3>Further explanation</h3>
Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.
The general structure is R-CHO with the molecular formula :

Naming is generally the same as the alkane by replacing the suffix with -al
Butanal or butyraldehyde is an aldehyde which has 4 C atoms
Inside the structure there are 3 atoms involved in bonding:
- 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
- 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
- 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet
In describing Lewis's structure the steps that can be taken are:
- 1. Count the number of valence electrons from atoms in a molecule
- 2. Give each bond a pair of electrons
- 3. The remaining electrons are given to the atomic terminal so that an octet is reached
- 4. The remaining electrons that still exist in the central atom
- 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds
In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom
<h3>Learn more:
</h3>
Adding electron dots
brainly.com/question/6085185
Ionic bonding
brainly.com/question/1603987
Formal charge
brainly.com/question/7190235
Keywords: butanal, aldehyde, Lewis structure, a valence electron
IV. Molasses will sink because it has a greater density. The rest will float or suspend.
Answer:
28.58 g of NaOH
Explanation:
The question is incomplete. The missing part is:
<em>"Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step"</em>
To do this, we need to know how much of the base we have to weight to prepare this solution.
First we know that is a sodium hydroxide aqueous solution so, this will dissociate in the ions:
NaOH -------> Na⁺ + OH⁻
As NaOH is a strong base, it will dissociate completely in solution, so, starting with the pH we need to calculate the concentration of OH⁻.
This can be done with the following expression:
14 = pH + pOH
and pOH = -log[OH⁻]
So all we have to do is solve for pOH and then, [OH⁻]. To get the pOH:
pOH = 14 - 13.9 = 0.10
[OH⁻] = 10⁽⁻⁰°¹⁰⁾
[OH⁻] = 0.794 M
Now that we have the concentration, let's calculate the moles that needs to be in the 900 mL:
n = M * V
n = 0.794 * 0.9
n = 0.7146 moles
Finally, to get the mass that need to be weighted, we need to molecular mass of NaOH which is 39.997 g/mol so the mass:
m = 39.997 * 0.7146
<h2>
m = 28.58 g</h2>