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4 years ago

1. Addition of which of the following will increase the solubility of CaCO3 in water? Consider the equilibrium process:

Chemistry

1 answer:

kolbaska11 [484]4 years ago

6 0

Answer: HCl

Explanation:

calcium carbonate dissolves in HCl acid producing CO 2 gas. It will not dissolve in pure water. The Ksp for calcium carbonate in water is 3.4 x 10-9 moldm-3 which is very low. What takes place here is actually a chemical reaction:

CaCO 3 (s) + 2HCl(aq) → CaCl 2 (aq) + H 2CO 3(aq)

This reaction accounts for the solubility of the Calcium carbonate in HCl and not in pure water.

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What makes a planet a terrestrial planet

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Veseljchak [2.6K]

Answer:

Its neither a myth nor deadly

Explanation:

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2 years ago

PLEASE HELP, I NEED TO GET THIS DONE TODAY

luda_lava [24]

The balanced reaction is

3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2

To balance this reaction of double displacement, we see first that this reaction maintain the valence numbers of every atom.

Then, to have the same value of Na in the two sides of the reaction we multiply for the number of the other side. So,

(Na3PO4)x 2

(Na2SO4)x3

As we can see either, we need to balance PO4 cause there are two molecules of this in the reactant side, so we have two molecules of PO4 in the product either.

Then we get

3Na3PO4 + 2CuSO4 ------> 3Na2SO4 + Cu3(PO4)2

To probe that balance was correct, you can verify that the charges are exactly the opposite.

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3 years ago

The citizens of a town are aware of climate change, and they want to make changes to control it. One change they consider is rep

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3 years ago

For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this

Salsk061 [2.6K]

The following are the steps to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3 N = +5

O = -2 O = -2

Ag = +1 Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

NO2– -----> NO3–

Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

NO2– + H2O -----> NO3–

Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

NO2– + H2O -----> NO3– + 2H+

Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

NO2– + H2O -----> NO3– + 2H+ + 2e-

Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

NO2– + H2O -----> NO3– + 2H+ + 2e-

2 Ag+ + 2e------> 2 Ag(s)

3 0

3 years ago