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3 years ago

Evaluate the expression for the given value of x 7x + 8 for x = 2

Mathematics

2 answers:

Pepsi [2]3 years ago

6 0

Replace x with 2
Then you’ll get: 7(2)+8
7x2=14
14+8=22
The answer is 22

Anit [1.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

Since x = 2, we can tell that x is equal to 2.

So this is basically asking 7 times 2 plus 8

7(2) + 8 = ?

14 + 8 = 22

Hope this helps!

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3 years ago

Write 2 1/2 miles in 3/4 hour as a unit rate

ValentinkaMS [17]

Answer:

3 1/3 mph

Step-by-step explanation:

2.5 ÷ 0.75 = 3.3

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3 years ago

Question 7 please help maths

Tcecarenko [31]

The formula is right there, Mr. President.
All you need to do is write the numbers you know into the correct
places in the formula, and then find the value of the fraction.

The formula: Density = (mass) / (volume)

You know:
mass = 67.5 grams
volume = 5 ml

Write them in the correct places in the formula:

   Density = (67.5 grams) / (5 ml)

   = (67.5 / 5) (grams / ml)

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5 0

3 years ago

Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul

Ivahew [28]

Answer:

a) $P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

b) $P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

c) $P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

d) $P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

e) $P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

Step-by-step explanation:

For this case we have the following cumulative distribution function:

$F(x) = 0 , x$

$F(x) = 0.7, 1 \leq x$

$F(x) = 0.9, 4 \leq x$

$F(x) = 1, x \geq 7$

Part a

We want this probability:

$P(X \leq 4)$

And we can find this using the cumulative distribution function:

$P(X \leq 4) = F(4) = 0.9$

Part b

We want this probability:

$P(X > 7)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >7) =1-P(X\leq 7)= 1- F(7) = 1-1 = 0$

Part c

We want this probability:

$P(X \leq 5)$

And we can find this using the cumulative distribution function:

$P(X \leq 5) = F(5) = 0.9$

Part d

We want this probability:

$P(X > 4)$

And we can find this using the cumulative distribution function and the complement rule on this way:

$P(X >4) =1-P(X\leq 4)= 1- F(4) = 1-0.9 = 0.1$

Part e

We want this probability:

$P(X \leq 2)$

And we can find this using the cumulative distribution function:

$P(X \leq 2) = F(2) = 0.7$

7 0

3 years ago

Create a linear regression equation that can be used to model the amount of money in the account (the balance), y, based on the

Karolina [17]

The regression equation is $\^y = 1.56\^x + 1.29$ , and it will take 31 weeks to have $50.00

<u>(a) The linear regression equation</u>

To do this, we make use of a graphing calculator;

From the graphing calculator, we have the following calculation summary:

The sum of X = 45
The sum of Y = 83
Mean X = 4.5
Mean Y = 8.3
Sum of squares (SSX) = 82.5
Sum of products (SP) = 128.5

The regression equation is then represented as:

$\^y = b\^x + a$

Where:

$b = \frac{SP}{SSX}$ and $a = M_Y - bM_X$

So, we have:

$b = \frac{128.5}{82.5}$

$b = 1.55758$

Approximate

$b = 1.56$

$a= 8.3 - (1.56 \times 4.5)$

$a= 1.29091$

Approximate

$a= 1.29$

This means that, the regression equation is $\^y = 1.56\^x + 1.29$

<u>(b) Predict the time to have $50.00</u>

This means that:

$\^y = 50$

So, we have:

$50 = 1.56\^x + 1.29$

Subtract 1.29 from both sides

$48.71 = 1.56\^x$

Divide both sides by 1.56

$31.22 = \^x$

Rewrite as:

$\^x = 31.22$

Approximate

$\^x = 31$

Hence, it will take 31 weeks to have $50.00

Read more about linear regression models at:

brainly.com/question/14585820

8 0

2 years ago