Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
244 divided by 60 = 4.0666
Hi there!
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I believe your answer is:
(0.286, 5.587)
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Here’s why:
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- I have graphed the two equations in a program. When graphed, the lines intersect at point (0.286, 5.587).
- See the graph attached.
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Hope this helps you. I apologize if it’s incorrect.
Answer: Cannot be done
Step-by-step explanation:
This is impossible as there is no previous information and we don’t have a formula.
Answer:
Rate = 0.45 or 45%.
Step-by-step explanation:
20184 = 9600(1 + r)^2
(1 + r)^2 = 20184/9600 = 2.1025
Taking square roots of both sides:
1 + r = 1.45
r = 1.45 - 1 = 0.45.
