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Aleksandr-060686 [28]
3 years ago
8

Nano purchased a computer for $800. If the sales tax rate was 8%, how much in all did he pay for the computer?

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

Nano paid $864 in total for the computer.

Step-by-step explanation:

The computer by itself is $800. Plus the 8% sales tax (8% of 800 is 64), that's $864 in total.

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Help!!!!
scZoUnD [109]

Answer:

13 or 14 pictures

Step-by-step explanation:

there are 27 students who has decided to be grouped in pair. pair means 2, so mathematically

27 = 2 *x 27 can't make a pair

where x is the one student is removed

number of 26 is left

pictures x = 26 \ 2

x = 27 \ 2 OR x = 13 pictures

x = 13.5

x = 14 pictures

hope it help

8 0
2 years ago
Write the equation of the line that passes through (1, -4) and (-4, 5). Put your answer in fully reduced point slope form unless
padilas [110]
Y+4=-9/5*(x-1)
Pls mark brainliest
7 0
3 years ago
Hi please answer and you dont NEED to show work but if u do i will give brainliest
Advocard [28]

Answer:

y=-\frac{2}{5} -1

Step-by-step explanation:

So first thing is that slope intercept form is setup like this

y=mx+b

m=slope

b=y intercept

the slope is change in y over change in x

as y goes down 2 x goes up 5

so the slope is -2/5

the y intercept is at (0,-1) so the y intercept is -1

therefore the answer is

y=-\frac{2}{5} -1

have a great day :)

8 0
3 years ago
Read 2 more answers
Find all the real square roots of -196.
Slav-nsk [51]
The answer is <span>-(3/4) and 3/4</span>
6 0
2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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