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navik [9.2K]
3 years ago
12

Use the periodic table to complete each nuclear fusion equation.

Chemistry
2 answers:
Verdich [7]3 years ago
6 0

Answer: A:5 B:2 C:15 D:8 E:O

Explanation:

just checked on edg

Misha Larkins [42]3 years ago
5 0

Answer:

a:5, b:2, c:15, d:8, e:O

For e its the letter o not zero

Explanation:

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10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?
Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles =  Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

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2 years ago
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3 years ago
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P4+ __02_ P4010 <br> I need help ASAP
klasskru [66]

Answer:

P_4+5O_2\rightarrow P_4O_{10}

Explanation:

Hello!

In this case, when we want to balance chemical reactions such as in this case, the idea is to equal to number of atoms of each element at each side of the equation according to the lay of conservation of mass, just as shown below:

P_4+5O_2\rightarrow P_4O_{10}

Because we have four phosphorous and ten oxygen atoms at each side.

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8 0
2 years ago
A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to
melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:

  • pH = pKa + log\frac{[CH_3COO^-]}{[CH_3COOH]}

For acetic acid, pKa = 4.75.

We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:

  • CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
  • CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:

  • pH = 4.75 + log\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L} = 5.54
6 0
3 years ago
What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?
Lorico [155]

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. <span>

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2) 

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O </span>

balancing the elements: <span>

<span>2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)</span></span>

6 0
2 years ago
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