Answer:
1.Respiration of animals and plants.
2.The burning of fossil fuels.
3.Bacteria decompose corpses.
Answer:
1. pH = 1.23.
2.
Explanation:
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1. In this case, for the ionization of H2C2O4, we can write:
It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:
Whereas the pKa is:
The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:
2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:
It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:
Which is also shown in net ionic notation.
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Answer:
Explanation:
We are asked to find how many moles of sodium carbonate are in 57.3 grams of the substance.
Carbonate is CO₃ and has an oxidation number of -2. Sodium is Na and has an oxidation number of +1. There must be 2 moles of sodium so the charge of the sodium balances the charge of the carbonate. The formula is Na₂CO₃.
We will convert grams to moles using the molar mass or the mass of 1 mole of a substance. They are found on the Periodic Table as the atomic masses, but the units are grams per mole instead of atomic mass units. Look up the molar masses of the individual elements.
- Na: 22.9897693 g/mol
- C: 12.011 g/mol
- O: 15.999 g/mol
Remember the formula contains subscripts. There are multiple moles of some elements in 1 mole of the compound. We multiply the element's molar mass by the subscript after it, then add everything together.
- Na₂ = 22.9897693 * 2= 45.9795386 g/mol
- O₃ = 15.999 * 3= 47.997 g/mol
- Na₂CO₃= 45.9795386 + 12.011 + 47.997 =105.9875386 g/mol
We will convert using dimensional analysis. Set up a ratio using the molar mass.
We are converting 57.3 grams to moles, so we multiply by this value.
Flip the ratio so the units of grams of sodium carbonate cancel.
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place to the right tells us to round the 0 up to a 1.
There are approximately <u>0.541 moles of sodium carbonate</u> in 57.3 grams.
Answer:
Combustion reaction
Explanation:
Let's consider the following balanced equation.
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
This reaction is known as a combustion reaction, in which a compound reacts with oxygen to form a compound of carbon and water.
- If the product is carbon dioxide, the combustion is complete.
- If the product is carbon monoxide or carbon, the combustion is incomplete.
Answer:
The pressure in atm calculated using the van der Waals' equation, is 337.2atm
Explanation:
This is the Van der Waals equation for real gases:
(P + a/v² ) ( v-b) = R .T
where P is pressure
v is Volume/mol
R is the gas constant and T, T° in K
a y b are constant for each gas, so those values are data, from the statement.
[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K
[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K
(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K
(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol
0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol
0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol
0.04181L/mol. P = 14.1 L.atm/mol
P = 14.1 L.atm/mol / 0.04181 mol/L
P = 337.2 atm