The decomposition of Al2O3 to form pure aluminum (Al) along with the release of oxygen (O2) gas can be represented by the following chemical reaction:
2Al2O3 → 4Al + 3O2
Based on the reaction stoichiometry:
2 moles of aluminum oxide decomposes to form 4 moles of pure aluminum
Therefore, if 29.0 moles of aluminum is recovered, then the moles of aluminum oxide required will be:
= 29.0 moles Al * 2 moles Al2O3/4 moles Al
= 14.5 moles of Al2O3
All you need to do the cross the charges and put it as suffixes.
D+2 + E-1 ----> DE2
answer is C
It is either D or B
Hope I helped
Answer:
It'll be increased by a factor of 16...
Explanation:
After 10 C = Doubles
After 20 C = 4 Times
After 30 C = 8 Times
After 40 C = 16 Times
(The rate of reaction doubles as per 10 C rise in temperature as calculated)