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ankoles [38]
3 years ago
10

What is 64.3-3x2 to the third power divide by 2

Mathematics
1 answer:
Grace [21]3 years ago
5 0
Pretty high number
99077.6435
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Please help, A sequence has the rule 4n+10, what is the 59th term?
djverab [1.8K]
4* 59+ 10= 246

The 59th term is 246~
5 0
4 years ago
If these two figures are similar what is the measure of the missing side length J?
Ray Of Light [21]
If the long side on both is 9ft and 3ft then 3•3 is 9 so for the short side you do the same. If the short side is 1ft and the other is "j" then it's 1•3 is 3.

1•3=3
Sorry if it's confusing the way I explained it.
3 0
3 years ago
2.16= with the repeating decimal being 6
Goshia [24]

Since the .16 is in the hundredths place, the fraction is 2 16/100, or 216/100

But if you need to simplify it it's 2 4/25, or 54/25

3 0
3 years ago
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
An isosceles triangle has congruent sides of 20 cm. The base is 10 cm. What is the
Alex_Xolod [135]

Answer:

100 cm

Step-by-step explanation:

The formula to answer this question is base x height divided by 2. All you have to do is substitute: 10x20= 200 divided by 2 is 100.

8 0
3 years ago
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