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3 years ago

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In a suvey of 100 out-patients who reported at a hospital one day it was find out that 70 complained of fever, 50 complained of

stomachs and 30 were injured. All 100 patients had at least one of the complains. How many patients had all three complains?

1 answer:

ruslelena [56]3 years ago

5 0

Just add them together
70+30+50=150
150-100=50
50 people had all three

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Answer:

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Answer:

2) The second option (the bag)

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Step-by-step explanation:

2)

O - Not certain, it is possible to choose a green marble

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O - Not certain, the spinner will not always land on the 10th letter of the alphabet

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3 years ago

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Ilya [14]

Let
x---------> <span>quantity (ton) of vegetables sold the first day
</span>y---------> quantity (ton) of vegetables sold the second day
z---------> quantity (ton) of vegetables sold the third day

we know that
x=y-3---------> equation 1
z=(5/9)*(x+y)------> equation 2
x+y+z=98-----> equation 3
substitute equation 2 in equation 3
x+y+[(5/9)*(x+y)]=98----> multiply by 9----> 9x+9y+5x+5y=882
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to resolve the equations system formed by
x=y-3
14x+14y=882

using a graph tool
see the attached figure
the solution is
x=30
y=33
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the answer is
vegetables sold the first day----> 30 ton
vegetables sold the second day----> 33 ton
vegetables sold the third day------> 35 ton

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