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Mathematics

1 answer:

aniked [119]2 years ago

6 0

A: x intercept is -2 and y intercept is -3

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The average annual salary of the employees of a company in the year 2005 was $70,000. It increased by the same factor each year

dezoksy [38]

We can make use of the general formula for the geometric series to generate the function representing the average annual salary.
an = a0(r)^(n-1)

Or
f(x) = a0(r)^(x - 1)

Plugging in the given values for the year 2005 and 2006 to ge the value of r.
82000 = 70000 (r)^(1-1)
r = 1.1714

Therefore, the function is:
f(x) = 70,000 (1.1714)^(x-1)

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2 years ago

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What value of x is in the solution set of 3(х – 4) > 5х + 2? 0—10 ОООО

MakcuM [25]

X < -7 hope this helps

4 0

2 years ago

SOMEONE HELP ASAP PLEASE

zavuch27 [327]

If the temperature drops, then you must have subtract amount of drop from initial temperature.
$-12,3^o-6,8^o=-(12,3^o+6,8^o)=-19,1^o$

The correct answer is the first one.

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3 years ago

In 2000, the population of Big Springs was 13 thousand. Use the given doubling

trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is t =0.

Formula:

$A= A_0e^{rt}$

Where,

$A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year$

for doubling time,

$r = \frac{log (2)}{t} \\$

$r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007$

Given value:

$A = A_0e^{rt} \\\\$

$A_0 = 13000$

$t= 40 \ years$

when year is 2000, t=0 so, year is 2100 year as t = 100.

$A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4$