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KIM [24]
3 years ago
12

Help!

Mathematics
1 answer:
aniked [119]3 years ago
6 0
A: x intercept is -2 and y intercept is -3
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In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.
Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=\frac{1}{2} \times s_1\times s_2\times sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^{\circ},

Thus, the area of the triangle PQR,

A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}

A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}

5 0
3 years ago
Determine whether the sequence is arithmetic, geometric, or neither, and justify your response.
Kobotan [32]

9514 1404 393

Answer:

  geometric

Step-by-step explanation:

The signs of the terms alternate, so it cannot be an arithmetic sequence.

The ratios of terms are ...

  6/-3 = -12/6 = 24/-12 = -2

The terms have a constant ratio of -2, so the sequence is geometric.

6 0
3 years ago
Which of the following numbers is Irrational?
sveticcg [70]

Answer:

I think its B I'm so sorry if its wrong

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If angle DBC = (9x + 1)°, angle ABC = 165°, and angle ABD = 38°,<br> find the value of x.
Step2247 [10]

Answer:

14.

Step-by-step explanation:

Hope this will help:)

3 0
3 years ago
Determine and state the maximum error of the function G(x,y,z)=20 ln⁡(xyz^2 ) using differentials when (x,y,z)=(2,3,4) and given
Leona [35]

Answer:

The maximum error in the function G, ΔG = ±4

Step-by-step explanation:

G(x,y,z) = 20 In (xyz²)

Total or maximum error for a multi-variable function is given by

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

(∂G/∂x) = 20yz²/xyz² = 20/x

(∂G/∂y) = 20xz²/xyz² = 20/y

(∂G/∂z) = 40xyz/xyz² = 40/z

Δx = ±0.10

Δy = ±0.15

Δz = ±0.20

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

ΔG = (20/x) (0.10) + (20/y) (0.15) + (40/z) (0.2)

At the point (x,y,z) = (2,3,4)

ΔG = (20/2) (0.10) + (20/3) (0.15) + (40/4) (0.2) = 10(0.10) + 20(0.05) + 10(0.2) = 1 + 1 + 2 = 4

ΔG = ±4

6 0
3 years ago
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