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3 years ago

In the diagram, the measure of angle 3 is 89°, and the measure of angle 6 is 88°.

Mathematics

2 answers:

Kobotan [32]3 years ago

8 0

91 because 180- 89=91

Mumz [18]3 years ago

5 0

Alright, lets get started.

Angle 3 and angle 4 are adjacent angles because they are having the common side.

They both are on straight line, so, their addition will be 180°.

Suppose angle 4 is x , hence

angle 4 + angle 3 = 180

$x + 89 = 180$

Subtracting 89 from both sides

$x + 89 - 89 = 180 - 89$

$x = 91$ °

Hence angle 4 is 91°. : Answer

Hope it will help :)

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zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago

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drek231 [11]

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2 years ago

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enyata [817]

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\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
4\frac{3}{4}&10\\\\
x&1
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3 years ago

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malfutka [58]

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Step-by-step explanation:

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2 years ago

tatyana61 [14]

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3 years ago