<h3>
Answer: 14</h3>
Explanation:
Pick two columns from the table to form the (x,y) points.
I'll pick the last two columns, since everything is positive here. So we have the points (2, 17) and (4, 45)
Apply the slope formula to those points
m = (y2 - y1)/(x2 - x1)
m = (45 - 17)/(4 - 2)
m = (28)/(2)
m = 14
The rate of change is 14.
Answer:
The area after 9 years will be 1,234 km^2
Step-by-step explanation:
In this question, we are tasked with calculating what the area of a certain forest that decreases at a certain percentage would be after some years.
To answer this question, we shall be using an exponential approximation.
Now, to use this exponential approximation, we shall be needing a supporting exponential mathematical equation.
This can be written as;
A = I(1-r)^t
where A is the new area we are looking for
I is the initial area which is 1700 according to the question
r is the rate of decrease which is 3.5% = 3.5/100 = 0.035
t is time which is 9 years according to the question
We plug these values and have the following;
A = 1700(1-0.035)^9
A = 1700(0.965)^9
A = 1,233.66
This is 1,234 km^2 to the nearest square kilometer
Short Answer f(x) down 5 units, left 2 units and right side up from g(x)
Step OneFind out what -g(x+2) is.
There are two steps to this. The first is to deal with the minus sign
(g(x)) = - x^2 + 5. Be very careful what you do next.
Put brackets around both terms on the right.
g(x) = (-x^2 + 5) Now put the minus sign in front of g(x) and another one in front of the brackets.
-g(x) = - (-x^2 + 5) Remove the brackets.
-g(x) = x^2 - 5
<em>Result</em>
So far g(x) moves down 5 units and opens upward.
Step TwoThe second step is to see what the x + 2 does.
-g(x + 2) = (x + 2)^2 - 5
The final result is that the graph opens upward, moves left 2 spaces and down 5.
There is a graph enclosed to show you the key steps.
The red graph is g(x) = x^2 - 5
The blue graph is g(x+2) = (x+2)^2 - 5
Answer to your question is 1
Answer:

Step-by-step explanation:
Because the function is symmetric about the y-axis, using the cosine function is most appropriate.
<u>Refer to the equation for a cosine function:</u>
<u />
<u />
Amplitude: 
Period: 
Phase shift: 
Midline: 
The amplitude would be the average of the maximum and minimum y-values of the function, which would be
.
The value of
in
represents the length of the period, so since the length of the period is
, this means that
.
The phase shift,
, describes the horizontal shift of a function. Because the phase shift is
, then we can set up the equation
where we determine
.
The midline (or vertical shift),
, is the horizontal line that passes through between the maximum and minimum points, which the function oscillates. In this case, the midline would be located at the line
, therefore,
.
Putting all our information together, your final equation is:
