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nataly862011 [7]
4 years ago
12

C3H2 + 502 + 3 CO2 + 4H20

Chemistry
1 answer:
nordsb [41]4 years ago
6 0

Answer: 6.2 moles

Explanation:

C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)

The balanced equation above shows the combustion of propane, C3H8 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O

The mole ratio of combustion are as follows:

1 mole of C3H8 react to produce 4 moles of H2O

1.55 mole of C3H8 will react to produce Z moles of H2O

To get the value of Z, cross multiply

Z x 1 mole = 1.55 mole x 4 mole

Z = 6.2 moles

Thus, 6.2 moles of water will be produced from 1.55 moles of propane

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How much of a sample remains after five half-lives have occurred?
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Answer:

1/32 of the original sample

Explanation:

We have to use the formula

N/No = (1/2)^t/t1/2

N= amount of radioactive sample left after n number of half lives

No= original amount of radioactive sample present

t= time taken for the amount of radioactive samples to reduce to N

t1/2= half-life of the radioactive sample

We have been told that t= five half lives. This implies that t= 5(t1/2)

N/No = (1/2)^5(t1/2)/t1/2

Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

N/No= (1/2)^5

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