Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,
pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
![\frac{[Deprotonated]}{[Protonated]}=0.01](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D%3D0.01)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
![\frac{[Protonated]}{[Deprotonated]}=100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BProtonated%5D%7D%7B%5BDeprotonated%5D%7D%3D100)
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
Answer:
cetacean i think thats the answer
The substitution product that is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
<h3>What is a substitution product?</h3>
A substitution product is a product that is gotten from a reaction in which a group of reactants is replaced by another group in the reaction.
Therefore, the substitution product is supposed to be favoured. The product with retention of configuration is expected to predominate slightly because the leaving group blocks the nucleophile.
Learn more about substitution reaction below.
brainly.com/question/10143438
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Answer:
A<em>=</em><em>4</em>
<em>B</em><em>=</em><em> </em><em>4</em><em>+</em><em>2</em><em> </em><em>=</em><em>6</em>
<em>C</em><em>=</em><em>C</em><em>arbon</em>
<em>D</em><em>=</em><em>10</em>
<em>E</em><em>=</em><em>22</em>
<em>F</em><em>=</em><em>Argon</em><em> </em>
Answer:
B) One way of solving this is to use dimensional analysis and cancel out grams to find volume.
A) density over mass is volume. Mass is 84.7 g and volume is 49.6 cm cubed
Explanation:
