1. Identify a conjugate acid-base pair in the reaction

1 answer:

Alona [7]4 years ago

6 0

A.
H20 and OH are a conjugate acid-base pair.

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levacccp [35]

Answer:

Total moles of ions are released in water are $1.131\times 10^{-5} mol$ .

Explanation:

Mass of calcium nitrate = $6.18\times 10^{-4} g$

Molar mass of calcium nitrate = 164 g/mol

Moles of calcium nitrate = $\frac{6.18\times 10^{-4} g}{164 g/mol}=3.77\times 10^{-6} mol$

$Ca(NO_3)_2(aq)\rightarrow Ca^{2+}(aq)+2NO_3^{-}(aq)$

According to reaction, 1 mole of calcium nitrate gives 1 mole of calcium ions, then $3.77\times 10^{-6}$ moles of calcium nitrate will give:

$1\times 3.77\times 10^{-6} mol=3.77\times 10^{-6} mol$ of calcium ions

According to reaction, 1 mole of calcium nitrate gives 2 mole of nitrate ions, then $3.77\times 10^{-6}$ moles of calcium nitrate will give:

$2\times 3.77\times 10^{-6} mol=7.54\times 10^{-6} mol$ of nitrate ions

Total moles of ions are released :

$3.77\times 10^{-6} mol+7.54\times 10^{-6} mol=11.31\times 10^{-6} mol\approx 1.131\times 10^{-5} mol$

6 0

3 years ago

chubhunter [2.5K]

Answer: D

Explanation: pH = - log( c). If c= 1.0 M. PH = 0, if c=0.001 M. PH = 3

3 0

3 years ago

Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

$C a_{3}\left(P O_{4}\right)_{2}$ solubility will increase, since it is basic in nature, on acidifying solubility increases.
$F e S$ being basic on acidification, the solubility increases.
$M g C O_{3}$ is alkaline in nature, it gets neutralized and there is no increase in acidity.
$M g B r_{2}$ is a salt and it shows no effect on acidification.
$A g I$ is a salt but insoluble in water and shows no effect on acidification.
$M g(O H)_{2}$ is strongly basic in nature, on acidifying the solubility increases.