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LiRa [457]
2 years ago
14

Ecologists often use modeling, instead of field studies, because it

Biology
2 answers:
hodyreva [135]2 years ago
8 0

Answer:

the answer is a

Explanation:

ANEK [815]2 years ago
5 0

Answer:

Answer is A. allow them to control all the variables involved.

Explanation:

Modelling in ecology means the use of constructed mathematical models for understanding of ecological processes and to predict or know how real it is for ecosystem to change.

Ecological modelling is useful in defining problems more precisely and clarity of concepts.

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Black fur is dominant to white fur in guinea pigs. If two guinea pigs (Bb) are crossed what color and in what percentage What is
mote1985 [20]

I believe that the odds are strong that the off-spring would be 1/4 black, 1/2 black and white, and 1/4 white:

Bb x Bb = ¼ BB (all black); ½ Bb (black and white ) ;¼ bb (all white).

4 0
3 years ago
Mycorrhizae are associations formed by fungi that grow on the roots of trees. These fungi penetrate into the roots of the trees.
eduard

i think the answer you want is The fungi share a mutualistic association with the trees

8 0
3 years ago
A population of rabbits follows the typical pattern of inheritance and the law of dominance for fur color. B is the allele for b
Zinaida [17]

There should be about 40 bunnies. Hope I helped!

3 0
3 years ago
Read 2 more answers
Why do all nuclei undergo mitosis at the same time?
Anastaziya [24]
An organism has syncytial nuclei, which leads to parasynchronous or synchronous mitosis and therefore, multiple nuclei undergo the process of mitosis at the same time. This happens to the nuceli present in one cytoplasm, i.e., one cell. 
3 0
3 years ago
Consider a locus with two alleles - B and b. B is dominant, while b is recessive. There is no mutation. B has a selective advant
Marat540 [252]

Answer:

0.09

Explanation:

<h3><u>Before selection</u></h3>

Total number in population = 1000

Genotype frequencies

Genotype frequency of BB = 500/1000 = 0.5

Genotype frequency of Bb = 250/1000 = 0.25

Genotype frequency of bb = 250/1000 = 0.25

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.5 + (0.25/2) = 0.625

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.25 + (0.25/2) = 0.375

<h3><u>After selection</u></h3>

We are told that after selection, the genotype frequency of bb is changed as they become 50% less fit. This means the frequency of bb individuals changes from 250 to 125 individuals (50% reduction).

Now the total number of individuals is 500 + 125 + 250 = 875.

Genotype frequencies

Genotype frequency of BB = 500/875 = 0.57

Genotype frequency of Bb = 250/875 = 0.29

Genotype frequency of bb = 125/875 = 0.14

Allele frequencies

Allele frequency of B = BB genotype frequency + half of the Bb genotype frequency = 0.57 + (0.29/2) = 0.715

Allele frequency of b = bb genotype frequency + half of the Bb genotype frequency = 0.14 + (0.29/2) = 0.285

<h3><u>Change in frequency of B after 1 generation</u></h3>

0.715 - 0.625 = 0.09

7 0
3 years ago
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