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amid [387]
3 years ago
7

Explain how to find which is greater 1 fourth of 13 or 1 third of 12

Mathematics
2 answers:
AnnZ [28]3 years ago
7 0
First, I would find both of the valued to compare them:

1 fourth of 13:
You do 1/4 * 13 to get 13/4

1 third of 12:
You do 1/3 * 12 to get 12/3 or 4/1

To compare them, you need to multiply the 4/1 by 4 to get a common denominator of 4.

Now we are comparing 13/4 and 16/4 Because 16 is larger than 13, 1 third of 12 would be larger

Hope this helps
anastassius [24]3 years ago
4 0
One third of 12 is greater because the pieces would be bigger.
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Please help meeeeee with this
aleksandrvk [35]
Alright, let's do all of these (though this is a bit long).
1.
The constant is 1.8. All other values are coefficients to variables, which as the name implies will change.
2.
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So, 4.2 *60 *60 = 15120 seconds.
3.
<span>−5x−4(x−6)=−3-5x-4(x-6)=-3
Let's move all x to one side, and all other numbers to another.
-5x-4(x-6)=-3-5x-4(x-6)=-3
x can be any value you want, if you actually solve this you'll only end up with -3 = -3, which is correct, of course.
Let me show you:
</span><span>−5x−4(x−6)=−3-5x-4(x-6)=-3
+5x +4(x-6)        +5x +4(x-6)
-3 = -3
The value of x is irrelevant, then. X can be any real number.
4.
I'm going to assume it was an error in printing with this? If not please correct me.
m=a+2b(or b2)
subtract 2b from each
a=m-2b
(This question seems kind of odd. We should probably address this in the comments.)
5.
</span><span>5(x−2)<−3x+6
Move all x to one side, numbers to other.
5x-10<-3x+6
+3x     +3x
    +10      +10
8x<16
/8
<span>x < 2
</span>6.
y-3=3(x-5)
alright, to find zeros set one variable to zero and solve
x first
-3=3x-15
+15    +15
3x=12
/3
x=4
x-int is (4,0)
now y
</span>y-3=3(0-5)
y-3=-15
+3     +3
y=-12
so y-int is (0,-12)
i've got to sleep now so i'll do the rest tomorrow. Sorry for the incomplete answer.

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