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2 years ago

Why does all heads or all tails seem less likely than random?

1 answer:

6 0

Of course in every situation, getting all heads or all tails will always have lower chances than the random result.
Random result basically had the chance of 100% of happening because its condition is still fulfilled no matter what the result of the coin toss is, meanwhile all heads or all tails has little probability.

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F(x) = x2 - 8x - 20<br> What is the axis of symmetry, vertex, and y intercept

igor_vitrenko [27]

1. vertex is -4 because:

x^2-8x-20,

a=1, b=-8 , c=-20

use vertex form! -b/2a = -8/2(1) = -8/2 = -4.

2. axis of symmatry is the x which is also -4. The same steps go for the second one.

3. y intercept, I think the answer is -20. Im not sure for this one.

IF YOU LIKE THIS ANSWER PLEASE GIVE ME BRAINLIEST.

5 0

2 years ago

Which of the following expressions are equivalent to this expression:

Gekata [30.6K]

The original expression is equal to 0 because anything multiplied by 0 is equal to 0. Solve inside the brackets for the possible answer choices to find what will equal 0.

Start with the first expression. Add 4 and negative 4 will become 0, and -1 times 0 is equal to 0. Let's solve for the others just to be sure.

In the second expression, solving inside the brackets gives you 8. -1 times 8 is equal to -8.

Adding 4 and negative 4 in the third expression leaves you with 0. But, 1 + 0 is equal to 1.

Adding negative 4 and negative 4 gives you the answer of -8, and -1 times -8 is equal to 8.

Your answer is the first expression, or A.

6 0

2 years ago

Read 2 more answers

Graph the set on the number line.

Ratling [72]

Here’s the answer w explanation :)

8 0

2 years ago

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in

Nuetrik [128]

<h2> $\large\bold{\underline{\underline{Question:-}}}$ </h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2> $\large\bold{\underline{\underline{Solution:-}}}$ </h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

$\underline{ \underline{ \sf{Let's \: find \: the \: ratio \: of \: their \: volumes:}}}$

${ \implies{ \sf {V _{1} : V_{2}}}}$

${ \implies{ \sf{ \frac{1}{3} \pi \: { r_{1}}^{2} h_{1} : \frac{1}{3} \pi \: { r_{2} }^{2} h_{2}}}}$

${ \implies{ \sf{ {r_{1}}^{2} h_{1} : { r_{2}}^{2} h_{2}}}}$

${ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} } : \frac{ h_{2} }{ h_{1} } }}} \\$

${ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} } : \frac{3}{1} }}} \\$

${ \implies{ \sf{ \frac{9}{1} : \frac{3}{1} }}} \\$

${ \implies{ \sf{3 : 1}}} \\$

${ \therefore{ \sf{ \green{Ratio \: of \: their \: volumes = 3 : 1}}}}$

4 0

2 years ago

Using a compass and straight edge, construct a tangent line to a circle from a given exterior point. Evidence of your constructi

AleksAgata [21]

In the figure attached, red circle A and red point B are the circle and external point of interest. Note that we must know where the center of circle A is. If we don't know that, there are construction techniques for finding it, but that is beyond the scope of this answer.

Step 1. Set your compass to a radius greater than half the length of segment AB. Here, we have made the radius AD.

Step 2. Draw arcs above and below the center of segment AB centered at A and B using the radius of Step 1. Here the "arc" is shown a a full (green) circle. Only the points where the arcs intersect (E and F) are of interest, so it is not necessary to draw the full circle.

Step 3. Identify the points of interesection (E and F) of the arcs of Step 2, then draw a line segment between them. This segment (EF) is the perpendicular bisector of AB. Mark point G where it intersects segment AB. As with the green circles, it is not necessary to draw the whole line EF, since we are only interested in the location of the midpoint of AB, which is point G.

Step 4. Using G as the center, and GA or GB as the radius, draw semicircle AHB. The point of intersection H is the only part of that (blue) circle of interest, so it is not necessary to draw the whole thing.

Step 5. Finish the consruction by drawing tangent line BH.

6 0

2 years ago