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pychu [463]
4 years ago
9

Spongebob loves to garden and wants to grow lots of pink flowers for his pal Sandy. He bought a special Flower Power fertilizer

to see if it will help his
plants produce more flowers. He plants three plants of the same size in separate containers with he same amount and type of potting soll. He places one
plant in a sunny window and waters It every day with fertilized water. He places the second plant in a more shady window and waters it every other day
with fertilized water. He places the third plant in a dark closet and waters it every day with plain water. What did Spongebob do wrong in this experiment?
he has no controlled variables
he has too many dependent variables
he has no control group
he has too many Independent variables
Chemistry
1 answer:
horrorfan [7]4 years ago
7 0

Explanation:

he has no controlled variables

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URGENT! Consider the following decomposition reaction of ammonium carbonate ((NH4)2CO3):
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<span>Using PV=nRT to find the moles and then convert back.
</span><span>4x=.8944
</span><span>solve for x then use the pressure for lets say CO2 put that into PV=nRT then solve for n then convert over.
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<span>(.2236)(2)/(298*.08206) = .0183*96g/mol = 1.76g
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<span>For C:

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3 years ago
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: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne
olchik [2.2K]

Answer:

The Net reaction is    

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

Explanation:

From the Question we are told that the buffers are

                H_2C_6H_5O_7^ - and  HC_6H_5O_7 ^{ 2-}

When NaOH is added the Net ionic reaction would be

  1.    H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction
  2.    H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH
  3.    HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH  

             

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