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3 years ago

What is the difference in uniformity between heterogeneous and homogeneous mixtures?

Chemistry

1 answer:

Aneli [31]3 years ago

4 0

Answer:

The correct answer according to the uniformity the difference is whether you can distinguish more than one part in the mixture.

Explanation:

A homogeneous mixture is one in which with the naked eye or with a microscope no different parts can be distinguished. Its composition and properties are the same at all points, the substance is uniform.

In a heterogeneous mixture, we can observe different parts. Its composition is variable. It can be broken down into simpler substances by physical processes. The substance, in this case, is not uniform.

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The table shows the students data from an investigation about a plant growth and five plants of the same type what is the best w

NARA [144]

Answer:

This question is incomplete

Explanation:

The question is incomplete because of the absence of the table but since the question says there are data from an investigation about a plant growth and five other plants (making six) of the same type, the best way to display this type of data for analyst is to use the grouped bar chart. The grouped bar chart will display the data obtained (from an investigation on plant growth) from different students on each of the six plants (of the the same type).

Colours are usually used to identify the bars (of a group) or could be used to separate the group from other groups but in this case, colours are better used to identify the bars of a group.

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3 years ago

What is the pOH value of 0.0000877 M HCL

vredina [299]

Answer:

pOH=9.9

Explanation:

pH=-log[H+]= -log[0.0000877]

=4.06

pOH+ pH=14

pOH=14-4.06= 9.91

8 0

2 years ago

how many particles of the part that orbits the nucleus is on the shell closest to the center of the atom?

kolezko [41]

There are 2 atoms orbiting it.

8 0

2 years ago

Read 2 more answers

What is the [OH-] of a substance that has a pH of 11?

Deffense [45]

Answer:

0.001 M OH-

Explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

6 0

2 years ago

A 1.68 g sample of water is injected into a closed evacuated 5.3 liter flask at 65°C. What percent (by mass) of the water will b

Angelina_Jolie [31]

Answer:

50.4 % of the water will be vapor

Explanation:

Step 1: Data given

Mass of water = 1.68 grams

volume of the flask = 5.3 L

Temperature = 65°C

Vapor pressure of water at 65°C = 187.5 mmHg = 0.2467 atm

Step 2: Calculate moles of H2O

p*V=n*R*T

⇒ p = the pressure of water = 0.2467 atm

⇒ V = the volume of the flask = 5.3 L

⇒ n = moles of water

⇒ R = gas constant = 0.08206 L*atm/ K*mol

⇒ T = the temperature = 65°C = 338 Kelvin

n = (p*V)/(R*T)

n = (0.2467 * 5.3) /(0.08206* 338)

n = 0.047 moles

Step 3: Calculate mass of water

Mass of water = moles of water * molar mass of water

Mass of water = 0.047 moles *18.02 g/mol

Mass of water = 0.84694 grams

Step 4: Calculate the percent of water vaporized

% = (0.84694 grams/1.68 grams) *100%

% = 50.4%

50.4 % of the water will be vapor

5 0

3 years ago