The question is on trigonometry. Sine of an angle is obtained using the SOH of SOHCAHTOA formula of trigonometry. SOH is an acronym for sine, opposite and hypotenuse. Sine of an angle is obtained from the ratio of opposite and hypotenuse of a given triangle. Thus, SOH

is denoted as stated below.

$sine \: \beta = \frac{opposite}{hypotenuse}$

Hence, given the above triangle,

$sine \: of \: angle \: u = \frac{ |bc| }{ |ab| } = \frac{55}{73}$

Therefore, the sine of angle u = 55/73 (D)

6 0

3 years ago

Find the equation of the linear function represented by the table below in slope-intercept form.

Naily [24]

Question: Where is the y2? Please be more specific!

3 0

2 years ago

A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th

kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

$V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s$

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s

8 0

3 years ago