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2 years ago

Solve the inequality and graph the solution |7x-7|+2<23

Mathematics

1 answer:

Naya [18.7K]2 years ago

3 0

$|7x-7|+2 < 23\ \ \ \ \ |-2\\\\|7x-7| < 21\iff7x-7 < 21\ \wedge\ 7x+7 > -21\ \ \ \ \ \ |+7\\\\7x < 28\ \wedge\ 7x > -14\ \ \ \ \ \ \ |:7\\\\x < 4\ \wedge\ x > -2\\\\-2 < x < 4$

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STatiana [176]

Answer:

x=-8

Step-by-step explanation:

Subtract 2 from both sides

Simplify

Multiply all terms by the same value to eliminate fraction denominators

Cancel multiplied terms that are in the denominator

Subtract 2x from both sides

Simplify

8 0

2 years ago

Read 2 more answers

Solve each equation.<br> Show all steps<br> 4) -8(-6-5k)=-232

Lubov Fominskaja [6]

the answer is k=4.6. hope this helps

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2 years ago

Write the explicit formula for the geometric sequence 2, 8, 32, 128

Alja [10]

The first term, a, is 2. The common ratio, r, is 4. Thus,

a_(n+1) = 2(4)^(n).

Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.

Try this instead:

a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.

The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.

3 0

2 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$