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AysviL [449]
3 years ago
15

How do the nonliving parts of earth's systems provide the basic materials to support life?

Physics
1 answer:
MatroZZZ [7]3 years ago
3 0
The abiotic community of the ecosystem or the nonliving objects in the earth's biosphere influences the survival, growth and development of the organism. They provide basic mmaterials to support life by the biogeochemical processes which is composed of many biological and environmental cycles which profoundly has factored the intiation and continuation of life on earth. They also provide the basic materials to support life by the undergoing process which is also initiated by the living creatures or the biotic society of the ecosystem.
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At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
swat32

Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

Where:

Q is the released heat by the system

n is the number of moles

ΔT is the difference of temperature of the system  

Now, we can find n with the molar mass (M) the mass of the compound (m).

n=\frac{m}{M}=6.95\cdot 10^{-3} moles      

Using (1) we have:

C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

C=1,25\cdot 10^{5} kJ/^{\circ}C

I hope it helps!

6 0
4 years ago
The element in a fluorescent lightbulb that absorbs UV light and releases visible light energy is ____?
Mnenie [13.5K]
So in a fluorescent light bulb the mercury atoms release the UV light. This UV light is absorbed by the phosphorous powder coating inside and this releases the visible light.
So your answer is phosphorous powder.
3 0
3 years ago
Read 2 more answers
A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara
saw5 [17]

Answer:

(a)\alpha = 53.73 m/s^2

(b)   I =428 kgm^2

(c)\tau = 428 \times 53.73  = 22996 .44Nm

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

\omega = \frac{v}{l}

\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s

for  angular acceleration, use the following equation.

\omega _{f}^2 = \omega_{i}^2+2\alpha\theta

since \omega _{i} = 0

here  for one circle is 2 π radians.   therefore for one quarter of a circle is π/2 radians

so   for one quarter \theta = \frac{\pi }{2}

(12.99)^2 = 2\alpha(\frac{\pi }{2})

on solving

\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2

(b)

For the catapult,

moment of inertia

I = \frac{1}{2}MR^2

I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2

For the ball,

I = MR^2

I = 18.2 \times 14.51

I = 264 kgm^2

so total moment of inertia =  428 kgm^2

(c)

\tau = I\alpha

\tau = 428 \times 53.73  = 22996 .44Nm

3 0
3 years ago
Which part of the wave is changed when there is interference?
Ne4ueva [31]
The amplitude is changed.
7 0
3 years ago
Read 2 more answers
Size relationships between parts of a whole are known as.
Stella [2.4K]

Answer:

proportion

Explanation:

hope it was helpful to you

then

plz mark me as brainlist

8 0
2 years ago
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