Answer:
250 N
433 N
Explanation:
N = Normal force by the surface of the inclined plane
W = Weight of the block = 500 N
f = static frictional force acting on the block
Parallel to incline, force equation is given as
f = W Sin30
f = (500) Sin30
f = 250 N
Perpendicular to incline force equation is given
N = W Cos30
N = (500) Cos30
N = 433 N
Answer:
180°
Explanation:
Friction, if it exists, ALWAYS opposes motion or attempted motion.
The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.
(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m
Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.
(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ
θ=37.69 degrees
Hopes this helps!
P.S. I hope this is right. If not sorry in advance.
Answer:
which language is these
Explanation:
we only use english , Hindi ,tamil , bengali and Malayalam
please tell us that it is which language. From that we will slove this
Answer:
380m
Explanation:
We have the speed of the spaceship v = 0.75c
Max measures contracted length L of the spaceship as it travels
We have been given L = 250m
As this ship stops he is going to get exact length of the ship = Lol
We solve using this formula
L = Lo√ 1-v²/c²
From the formula above we make Lo subject of the formula
When we input values
Lo = 250/√1-(0.75c/c)²
= 250/√1-(0.75)²
= 250/√0.4375
= 250/0.6614
= 377.98
This is approximately 380
