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joja [24]
3 years ago
5

The ability of a material to bend without breaking

Physics
1 answer:
My name is Ann [436]3 years ago
5 0
Im pretty sure the answer if elasticity
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A proton with mass 1.67*10^-27kg is propelled at an initialspeed of 3.00*10^5m/s directly toward a uranium nucleus 5.00maway. Th
Tresset [83]

Answer:

Explanation:

F = 2.12 x 10⁻²⁶ / x²

Work done by electric field of nucleus

W = ∫ Fdx

= ∫2.12 x 10⁻²⁶ / x² dx

= 2.12 x 10⁻²⁶ ( - 1 / x )

= - 2.12 x 10⁻²⁶ ( 1/5 - 1 / 8 x 10⁻¹⁰ )

= - .265 x 10⁻¹⁶ J

1/ 2 x mv² = .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ - .265 x 10⁻¹⁶

= 7.515 x 10⁻¹⁷ - .265 x 10⁻¹⁶

=( .7515 - .265 )x 10⁻¹⁶

= .4865 x 10⁻¹⁶

.5 x 1.67 x 10⁻²⁷ x v² = .4865 x 10⁻¹⁶

v² = .5826 x 10¹¹

v² = 5.826 x 10¹⁰

v = 2.41 x 10⁵ m /s

b )

Let r be the closest distance

Potential at this point

2.12 x 10⁻²⁶ (  1 / r )

Kinetic energy

= 0

Total energy = 2.12 x 10⁻²⁶ (  1 / r )

Total energy at 5 m

= .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ + 0 ( potential energy at 5 m will be negligible as compared with that near the center )

= 7.515 x 10⁻¹⁷ J

So ,

2.12 x 10⁻²⁶ (  1 / r ) = 7.515 x 10⁻¹⁷

r = 2.12 x 10⁻²⁶ / 7.515 x 10⁻¹⁷

= .282 x 10⁻⁹

= 2.82 x 10⁻¹⁰ m

c ) As electric field is conservative , no dissipation of energy takes place . Hence its speed at 5m on returning back to this point will be same as

3.00 x 10⁵ m /s

7 0
4 years ago
An astronaut is traveling in a space vehicle moving at 0.490c relative to the Earth. The astronaut measures her pulse rate at 66
marta [7]

To solve the exercise it is necessary to use the reciprocal Lorenz factor of the special theory of relativity with the pulse rate.

\Xi = Pulse_{astronaut} * \alpha

Where,

\Xi = Pulse rate measured by earth observed

\alpha = Reciprocal Lorenz Factor

\alpha = \sqrt{1-\frac{v^2}{c^2}}

Here v is the velocity and c the light speed.

PART A) For the given values we can replace it at the previous equation,

\Xi = Pulse_{astronaut} *\sqrt{1-\frac{v^2}{c^2}}

\Xi = 66beats/min * \sqrt{1-\frac{(0.49c)^2}{c^2}}

\Xi = 57.5beats/min

PART B ) If the speed of vehicle is 0.94c:

\Xi = Pulse_{astronaut} *\sqrt{1-\frac{v^2}{c^2}}

\Xi = 66beats/min * \sqrt{1-\frac{(0.94c)^2}{c^2}}

\Xi = 22.5beats/min

8 0
3 years ago
Rank the nonmetals in each set from most reactive (1) to least reactive (3). Bromine: Chlorine: Iodine:
ANEK [815]

The most reactive element of this list is Chlorine, the next most reactive is bromine, and the least reactive is iodine.

All of these three elements are group 7 elements in the periodic table. It is known that the reactivity of group 7 elements decreases down the group. The most reactive element in this group is Flourine  with reactivity decreasing down the group.

The reason for this decrease in reactivity is that as you go down the group, the distance between the positive nucleus that attracts valence electrons increases, decreasing the electrostatic attraction between the nucleus and the outer electrons. The other reason is that the electrons in lower energy levels closer to the nucleus repel and shield the electrons in the outermost shell or energy level of the atom.

Chlorine>Bromine>Iodine.

6 0
4 years ago
Read 2 more answers
The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel ​
yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

take the reciprocal of all the resistances: 1/15, 1/65, 1/35

then add them: = 151/1365

then reciprocal the answer: =1365/151

And chuck it on a calculator: =9.04 Ohms

I think this is right but I'm not entirely sure. Tell me if I'm right by the way!

3 0
3 years ago
At Magic Mountain there is a ride in which people stand up against the inside wall of a large cylinder of radius 3 m. The cylind
mafiozo [28]

Answer:

0.1308

Explanation:

To keep the rider from sliding down, then the friction force F_f must at least be equal to gravity force F_p

F_f = F_p

\mu N = mg

where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.

According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force F_c, which is the product of centripetal acceleration a_c and object mass m

N = F_c = a_cm

Therefore

\mu a_cm = mg

\mu a_c = g

The centripetal acceleration is the ratio of velocity squared and the radius of rotation

a_c = v^2/r = 15^2 / 3 = 75 m/s^2

Therefore

\mu = g/a_c = 9.81 / 75 = 0.1308

3 0
3 years ago
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