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Ksivusya [100]
2 years ago
13

Help me

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Physics
1 answer:
elixir [45]2 years ago
8 0

Answer:

<em>1</em><em>)</em><em> </em><em>P</em><em>late</em><em> </em><em>tectonic</em><em> </em><em>theory</em>

<em>2</em><em>)</em><em> </em><em>Lithospheric</em>

<em>3</em><em>)</em><em> </em><em>Plates</em>

<em>4</em><em>)</em><em> </em><em>Heat</em>

<em>5</em><em>)</em><em> </em><em>Less</em><em> </em><em>dense</em>

<em>6</em><em>)</em><em> </em><em>Conventional current</em>

<em>7</em><em>)</em><em> </em><em>Magma</em>

<em>8</em><em>)</em><em> </em><em>Ocean</em><em> </em><em>crust</em>

<em>9</em><em>)</em><em> </em><em>Slowly</em>

<em>10</em><em>)</em><em> </em><em>Drifting</em><em> </em><em>away</em><em> </em>

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determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if per
krok68 [10]

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m  therefore  r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

depth of immersion = 'h'

<u>Determine the metacentric height </u>

weight of cylinder in water = water displaced

= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h

= 0.6 * 4 = h

∴ h = 2.4 m

hence the depth of center of buoyancy from free space = h /2 = 1.2 m

The metacentric height can be calculated using the formula below

Gm = Io / Vsubmerged  - BG

attached below is the remaining solution

6 0
3 years ago
The solid steel shaft AC has a diameter of 25 mm and is supported by smooth bearings at D and E. It is coupled to a motor at C ,
Degger [83]

Answer:

Maximum shear stress in region AB=1.04 MPa

Maximum shear stress in region BC=3.11 MPa

Explanation:

The explanation is attached in the attachments.

4 0
3 years ago
1. Calculate the total heat content of 10 kg of ice at -23°C.?
vesna_86 [32]

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) ( 2090 J/ Kg C) ( -23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) ( 4180 J/kg C) ( 60 C)

<span>H = 2508000 J</span>

8 0
3 years ago
A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8
Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

\eta =1-\frac{T_c}{T_h}

where,

\eta = efficiency = 0.780

T_h = Temperature of hot reservoir = ?

T_c = Temperature of cold reservoir = -24.8^oC=273+(-24.8)=248.2K

Now put all the given values in the above expression, we get:

\eta =1-\frac{T_c}{T_h}

0.780=1-\frac{248.2K}{T_h}

T_h=1128.18K

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0
3 years ago
How can global climate change be studied
Marina CMI [18]
Not sure... need help with it 


4 0
3 years ago
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