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bezimeni [28]
3 years ago
5

How do you turn 5x + 4y =8 into. Y= mx+ b

Mathematics
2 answers:
yulyashka [42]3 years ago
4 0
5x+4y= 8
-5. -5

4y= 3x+8
Divide 4 on both sides
Y= 3/4+2
olga nikolaevna [1]3 years ago
3 0

Answer:

5x+4y=8

4y=8-5x

4y/4=8-5x/4

y=8-1.25x

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3 years ago
Da sofa is on sale for $98.60, which is 29% of the regular price. What is the regular price ?
yaroslaw [1]
Let the regular price be X
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4 0
3 years ago
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5 0
3 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
Combine like terms to create an equivalent expression: -n + (-4) - (-4n) + 6
Taya2010 [7]

Answer:

3n + 2

Step-by-step explanation:

-n + 4n -4 + 6

3n + 2

6 0
3 years ago
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