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3 years ago

How do you turn 5x + 4y =8 into. Y= mx+ b

Mathematics

2 answers:

yulyashka [42]3 years ago

4 0

5x+4y= 8
-5. -5

4y= 3x+8
Divide 4 on both sides
Y= 3/4+2

olga nikolaevna [1]3 years ago

3 0

Answer:

5x+4y=8

4y=8-5x

4y/4=8-5x/4

y=8-1.25x

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Suppose that y varies directly with x and y = 10 when x = 20. What is y when x = 15?

aev [14]

Given that,

y varies directly with x and y = 10 when x = 20.

To find,

The value of y when x = 15.

Solution,

$y\propto x\\\\y=kx$

Put x = 20 and y = 10

$k=\dfrac{y}{x}\\\\k=\dfrac{10}{20}\\\\=\dfrac{1}{2}$

Put k = 1/2 and x = 15 to find the value of y.

$y=\dfrac{1}{2}\times 15\\\\=7.5$

So, the value of y is 7.5

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3 years ago

WILL MARK BRAINLIEST PLSS HELPPP.Triangle RST has vertices R(–1, 1), S(3, 1), and T(3, –4). What

Nataliya [291]

Answer:

first choice

Step-by-step explanation:

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3 years ago

Find the difference of the complex numbers.

Amiraneli [1.4K]

Answer:

D. 7 +11i

Step-by-step explanation:

In many situations, you can treat "i" as though it were a variable. Collect terms in the usual way.

(2 +8i) -(-5-3i) = 2 +8i +5 +3i = (2+5) +(8+3)i

= 7 +11i

6 0

3 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

3 years ago

What ratio is proportional to 18/21

Doss [256]

Answer:

There are many.

Step-by-step explanation:

When you say proportional, you are looking for a ratio that is equivalent to the ratio given. In your case, there are many so you might need to be more specific. But still, we can help you figure it out.

An easy way to do this would be to scale it down to its simplest form and then move upwards. To find proportional ratios, just multiply denominator and the denominator with the same factor.

$\dfrac{18}{21} = \dfrac{6}{7}$

That is your ratio in its simplest form. Now we can scale up, I'll show you how to do one completely:

$\dfrac{6}{7} x \dfrac{2}{2} = \dfrac{12}{14}$

That's the same ratio scaled up by a factor of 2.

---------------------------------------------------------------------------------------

$\dfrac{6}{7} x \dfrac{3}{3} = \dfrac{18}{21}$

That's the ratio given

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$\dfrac{6}{7} x \dfrac{4}{4} = \dfrac{24}{28}$

Scaled up by a factor of 4

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$\dfrac{6}{7} x \dfrac{5}{5} = \dfrac{30}{35}$

Scaled up by a factor of 5.

The list goes on and on.

3 0

3 years ago