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Vinvika [58]
3 years ago
11

1.) A man invested $600 at 8% per annum for 5 years. Calculate: a.) The simple interest payable b.) The total amount of money th

e man collected at the end of the 5-year period. 2.) Mr. Ford invested $12 450 in a bank at 7.25% per annum simple interest for 6 years. Calculate: a.) The interest he was paid b.) The total of amount of money he would have received at the end of the period of investment. 3.) The simple on $15 000 for 9 years is interest is paid when $800 is invested for 5 years.
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

Using formula:

\text{Simple Interest} = \frac{P \times R \times T}{100} \\\\\text{ Total amount} = \text{principle}+  \text{Simple Interest}

In question (1):

Principle= \$ 600\\Rate = \ 8 \%\\Time= \ 5

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(600 \times  8 \times 5)}{100}\\\\ \to  240

In point b:

\to amount = principle \ +\ simple \ interest

                 = 600 + 240 \\\\= 840

In question (2):

Principle= \$ 12,450\\Rate = \ 7.25 \%\\Time= \ 6

In point a:

\to \frac{P \times R \times T}{100} \\\\\to \frac{(12,450 \times  7.25 \times 6)}{100}\\\\ \to  5,415.75

In point b:

\to amount = principle \ +\ simple \ interest

                 = 12,450 + 5,415.75 \\\\= 17,865.75

The 3 question is incomplete, that's why it can't be solved.

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Answer:

x = 4

Step-by-step explanation:

We assume that the given expessions represent the measures of the alternate interior angles, so are equal.

... (4x + 12)° = 7x°

... 12 = 3x . . . . . . . divide by degrees, subtract 4x

... 4 = x . . . . . . . . . divide by 3

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3 years ago
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Answer:

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Triangle C:

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- longer leg = 7

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Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

<u>Triangle A</u>

The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

SL_{A} = 8 - 5 = 3

Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

LL_{A} = 2 - (-8) = 10

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Now, we can find the hypotenuse (H) by using Pitagoras:

H_{A} = \sqrt{SL_{A}^{2} + LL_{A}^{2}} = \sqrt{3^{2} + 10^{2}} = 10.4

<u>Triangle B</u>

The SL is from (3, -9) to (7, -9)

The length of the SL is:

SL_{B} = 7 - 3 = 4

The LL is from (7, -9) to (7, 4)

The length of the LL is:

LL_{B} = 4 - (-9) = 13

The hypotenuse is:

H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6

<u>Triangle C</u>

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

SL_{C} = -1 - (-6) = 5

The LL is from (-10, -6) to (-3, -6)  

The length of the LL is:

LL_{C} = -3 - (-10) = 7

The hypotenuse is:

H_{C} = \sqrt{5^{2} + 7^{2}} = 8.6

I hope it helps you!

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