The answer is B(11, 2sqrt(12) )
proof
the main equation of the circle is (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center
so if the center is the origin, it is O(0,0), and the equation becomes
<span> (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13
and for <span>B(11, 2sqrt(12) ) </span>11²+ (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
Step-by-step explanation:
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
Answer:
The value of each expression when x=3 will be -20 and -20.
Step-by-step explanation:
Given the expression
-4x-8
setting x=3
= -4(3)-8
=-12-8
=-20
Given the expression
-2(x+1)-2(x+3)
setting x=3
=-2(3+1)-2(3+3)
=-2(4)-2(6)
=-8-12
=-20
so we conclude that the value of both the expressions was -20 when we substituted the value x=3.
Therefore, the value of each expression when x=3 will be -20 and -20.
Answer:
<h2>1/4</h2>
Step-by-step explanation:
Area of a circle is given as πr² and its circumference is expressed as 2πr.
If the babylonians determined the area of a circle by taking it as equal to the square of the circle’s circumference then;
Area of circle = (circumference of a circle)²
πr² = (2πr)²
πr² = 4π²r²
Dividing both sides of the equation by πr² we have;
The value of π this yields is 1/4
