Help me Graph this Linear function 3y + 4y = 12

Simplify. (-2a^7y^4)(4ay^2)

dybincka [34]

Answer:

$-8a^8y^6$

Step-by-step explanation:

<h2>Lesson : Simplifying:</h2><h2></h2><h2></h2>

Given:

$(-2a^7y^4)(4ay^2)$

"Simplifying"

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$(-2a^7y^4)(4ay^2)$

Remove the parenthesis

$-2a^7y^4\cdot \:4ay^2$

Multiply the numbers

$-8a^7ay^4y^2$

Apply the exponent rule

$-8y^4a^{7+1}y^2$

Add the numbers

$-8y^4a^8y^2$

Apply the exponent rule once again

$-8a^8y^{4+2}$

Add the numbers once again

$-8a^8y^6$

5 0

4 years ago

Helpndmdkdkdndnfndndkdkdmd

alekssr [168]

I read this story last year for my 7th grade year. The correct answer is A!

6 0

3 years ago

Audrey measures the distance around the lid of her aquarium. The picture

Neporo4naja [7]

Answer: 10 inches
Explanation: You are given one side of the aquarium which is 18 inches. The top and the bottom of the aquarium is 18 inches because that’s what the diagram gives us. So you can multiply 18 x 2=36. Now, to find the missing side length, subtract the perimeter (56 inches) by 36 and you get 20 inches. However, that’s not your final answer because you have to divide 20/2=10 inches. 10 inches is the missing side length for the left and right side lengths.

7 0

3 years ago

Find the measure of the exterior angle.

MaRussiya [10]

Answer:

$120 \degree$

Step-by-step explanation:

The exterior angle in a triangle is equal to the sum of the interior opposite angles in a triangle

Therefore,

$90 + x = 4x$

Now solve for x

$90 + x = 4x \\ 90 = 4x - x \\ 90 = 3x \\ \frac{90}{3} = \frac{3x}{3} \\ 30 \degree = x$

Now let's solve for the exterior angle

$4x \\ 4 \times 30 \\ 120 \degree$

Hope this helps you.

Let me know if you have any other questions :-)

4 0

3 years ago

What's the intuition behind the equation 1+2+3+⋯=−1121+2+3+⋯=−112 ?

Aleks [24]

The sum clearly diverges. This is indisputable. The point of the claim above, that

$1+2+3+\cdots=-\dfrac1{12}$

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it $C$ . Then

$\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}$

Now, recall the geometric power series

$\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}$

which holds for any $|x|$ . It has derivative

$\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}$

Taking $x=-1$ , we end up with

$1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14$

and so

$-3C=\dfrac14\implies C=-\dfrac1{12}$

But as mentioned above, neither power series converges unless $|x|$ . What Ramanujan did was to consider the sum $1-2+3-4+\cdots$ as a limit of the power series evaluated at $x=-1$ :

$\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14$

then arrived at the conclusion that $C=-\dfrac1{12}$ .

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.

4 0

3 years ago