Answer:
The 10th term is 39366
Step-by-step explanation:
The n-th term in a geometric progression is
![T_n = a {r}^{n - 1}](https://tex.z-dn.net/?f=T_n%20%3D%20a%20%7Br%7D%5E%7Bn%20-%201%7D%20)
The third term is
![T_3 = a {r}^{2} = 18](https://tex.z-dn.net/?f=T_3%20%3D%20a%20%7Br%7D%5E%7B2%7D%20%20%3D%2018)
The 6th term is
![T_6 = a {r}^{5} = 486](https://tex.z-dn.net/?f=T_6%20%3D%20a%20%7Br%7D%5E%7B5%7D%20%20%3D%20486)
Let us take the ratio:
![\frac{T_6}{T_3} = \frac{a {r}^{5} }{a {r}^{2} } = \frac{486}{18} = 27](https://tex.z-dn.net/?f=%20%5Cfrac%7BT_6%7D%7BT_3%7D%20%20%3D%20%20%5Cfrac%7Ba%20%7Br%7D%5E%7B5%7D%20%7D%7Ba%20%7Br%7D%5E%7B2%7D%20%7D%20%20%20%3D%20%5Cfrac%7B486%7D%7B18%7D%20%20%3D%2027)
This means that:
![{r}^{3} = 27](https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B3%7D%20%20%3D%2027)
![r = \sqrt[3]{27} = 3](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203)
Put this into the 3rd term
![a \times {3}^{2} = 18](https://tex.z-dn.net/?f=a%20%5Ctimes%20%20%7B3%7D%5E%7B2%7D%20%20%3D%2018)
![9a = 18](https://tex.z-dn.net/?f=9a%20%3D%2018)
![a = 2](https://tex.z-dn.net/?f=a%20%3D%202)
The 10th term is:
![T_ {10} = a {r}^9](https://tex.z-dn.net/?f=T_%20%7B10%7D%20%3D%20a%20%7Br%7D%5E9)
![T_ {10} = 2 \times {3}^{9}= 39366](https://tex.z-dn.net/?f=T_%20%7B10%7D%20%3D%202%20%5Ctimes%20%20%7B3%7D%5E%7B9%7D%3D%2039366)
Thanks. Here is your answer:
Based on the image from the last questions the answer would most probably be B.
Answer:
73
Step-by-step explanation:
The answer for this question is letter c
The answer is 200 I think
Good luck